Aussie NSW Year 12 Projectile Motion Question.

In summary, a projectile with a time of flight of 7.5 seconds and a range of 1200 meters has an initial horizontal velocity of 160 m/s, a maximum height of 68.91 meters, and a final velocity of 90.67 m/s. The equation for calculating horizontal velocity is r = uxt, and for calculating maximum height is dy = uyt + (ayt2/2). The equation for calculating initial velocity is ux2 + uy2 = u, and for calculating final velocity is v = u + at.
  • #1
f3nr15
22
0

Homework Statement



A projectile has a time of flight 7.5s and a range 1200m
calculate
(a) its horizontal velocity
(b) Its maximum height
(c) the velocity witch which it is produced

I take ay as -9.8ms-2

Homework Equations



r = uxt
dy = uyt + (ayt2/2)
vy2 = uy2 + 2ah
ux2 + uy2 = u
v = u + at

The Attempt at a Solution



I hope I am the correct

a) r = uxt

ux = r/t
ux = 1200/7.5
ux = 160m

.: Initial Horizontal Velocity is 160m

b)

dy = uyt + (at2/2)

dy = 0 (Total vertical displacement is zero)
0 = 7.5uy - 275.625
7.5uy = 275.625
uy = 36.75

vy2 = uy2 + 2ah

vy = 0
0 = 1350.5625 - 19.6h
19.6h = 1350.5625
h = 68.90625 ...

.: Maximum height is 68.91m-1

c)

ux2 + uy2 = u

(160)2 + (36.75)2 = 26950.5625
u = 164.1662648 ...

.: Initial Velocity is 164.17ms-1

v = u + at

v = (164.1662648) + (-9.8)(7.5)
v = 90.6662648 ...

.: Final Velocity is 90.67ms-1


Ya ?
 
Physics news on Phys.org
  • #2
f3nr15 said:

Homework Statement



A projectile has a time of flight 7.5s and a range 1200m
calculate
(a) its horizontal velocity
(b) Its maximum height
(c) the velocity witch which it is produced

I take ay as -9.8ms-2

Homework Equations



r = uxt
dy = uyt + (ayt2/2)
vy2 = uy2 + 2ah
ux2 + uy2 = u
v = u + at

The Attempt at a Solution



I hope I am the correct

a) r = uxt

ux = r/t
ux = 1200/7.5
ux = 160m

.: Initial Horizontal Velocity is 160m

b)

dy = uyt + (at2/2)

dy = 0 (Total vertical displacement is zero)
0 = 7.5uy - 275.625
7.5uy = 275.625
uy = 36.75

vy2 = uy2 + 2ah

vy = 0
0 = 1350.5625 - 19.6h
19.6h = 1350.5625
h = 68.90625 ...

.: Maximum height is 68.91m-1

c)

ux2 + uy2 = u

(160)2 + (36.75)2 = 26950.5625
u = 164.1662648 ...

.: Initial Velocity is 164.17ms-1

v = u + at

v = (164.1662648) + (-9.8)(7.5)
v = 90.6662648 ...

.: Final Velocity is 90.67ms-1


Ya ?
a, b, and c look correct numerically, but your units generally are not. Then you added a part d which is not correct. You've got to look in the vertical and horizontal direction separately. Since energy is conserved, what might the final velocity be?
 
  • #3


I would say that your calculations and equations appear to be correct. However, it would be helpful to show your units in your calculations, as it is important to keep track of the units in order to get the correct final answer. Also, it would be helpful to explain your reasoning behind using certain equations and how they relate to the given information. Overall, it seems like you have a good understanding of projectile motion and were able to successfully solve the problem.
 

Related to Aussie NSW Year 12 Projectile Motion Question.

1. What is the purpose of this question?

The purpose of this question is to test the understanding and application of the principles of projectile motion in a real-world scenario.

2. What are the key concepts that are being assessed in this question?

The key concepts being assessed in this question include velocity, acceleration, angle of launch, and the effects of air resistance on a projectile's motion.

3. How should I approach solving this question?

You should first identify the given information, such as the initial velocity, angle of launch, and the height of the building. Then, use the equations of projectile motion to calculate the horizontal and vertical components of the projectile's motion. Finally, use these components to answer the specific questions asked in the problem.

4. How do I know if I have solved the question correctly?

You can check your answer by plugging it back into the given information and equations to see if it satisfies all the conditions. Additionally, if your answer makes logical sense and is within a reasonable range, it is likely correct.

5. What are some common mistakes to avoid when solving this type of question?

Some common mistakes to avoid include using the incorrect equations, not properly converting units, and forgetting to account for air resistance. It is also important to carefully read the question and pay attention to the given information to avoid any misunderstandings.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
1K
Back
Top