Application of Quadratic Functions that involve finding equation

In summary, after solving for the jet's speed from Tokyo to Bangkok and correcting some algebra mistakes, it was determined that the jet's speed from Bangkok to Tokyo is 600 km/h.
  • #1
Evangeline101
112
5

Homework Statement


upload_2016-5-21_13-36-25.png


Homework Equations


none

The Attempt at a Solution


upload_2016-5-21_13-37-47.png


Is this correct?

Thanks.
 
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  • #2
Evangeline101 said:

Homework Statement


[ ATTACH=full]101053[/ATTACH]

Homework Equations


none

The Attempt at a Solution


[ ATTACH=full]101054[/ATTACH]

Is this correct?

Thanks.
The answer is correct.

There are errors in your work starting with the table.

If x is the speed from Tokyo to Bangkok then reducing that by 200 gives a speed of x - 200 from Bangkok to Tokyo. Etc.
 
  • #3
Evangeline101 said:

Homework Statement


View attachment 101053

Homework Equations


none

The Attempt at a Solution


View attachment 101054

Is this correct?

Thanks.

Plug it in and see if it works.
 
  • #4
SammyS said:
The answer is correct.

There are errors in your work starting with the table.

If x is the speed from Tokyo to Bangkok then reducing that by 200 gives a speed of x - 200 from Bangkok to Tokyo. Etc.

I understand where I made the error, the return trip speed decreased by 200 km/h, so it should have been (x-200) not (x+200), so I have corrected my answer:
upload_2016-5-22_14-8-50.png


Thanks for the help! :)
 
  • #5
Evangeline101 said:
I understand where I made the error, the return trip speed decreased by 200 km/h, so it should have been (x-200) not (x+200), so I have corrected my answer:[ ATTACH=full]101104[/ATTACH]

Thanks for the help! :)
There's still a problem, x is the Tokyo to Bangkok speed. That can't be 600mph. 600 - 200 is 400, and that doesn't work out.

So, where is the problem?

You made a couple of errors.

Sign errors in going from
##-960000=2x^2-400x ##​
to
##2x^2+400x-960000= 0 ##​
It should be
##2x^2-400x+960000= 0 ##​
But there is no real solution to that.

The problem is that it's the Tokyo to Bangkok time that's smaller, because the speed is greater. When you subtract to get 2 hours, you need to subtract in the opposite order.
 
  • #6
SammyS said:
There's still a problem, x is the Tokyo to Bangkok speed. That can't be 600mph. 600 - 200 is 400, and that doesn't work out.

So, where is the problem?

You made a couple of errors.

Sign errors in going from
−960000=2x2−400x−960000=2x2−400x-960000=2x^2-400x to
2x2+400x−960000=02x2+400x−960000=02x^2+400x-960000= 0 It should be
2x2−400x+960000=02x2−400x+960000=02x^2-400x+960000= 0 But there is no real solution to that.
I tried doing it this way, but as you said there is no real solution.
SammyS said:
The problem is that it's the Tokyo to Bangkok time that's smaller, because the speed is greater. When you subtract to get 2 hours, you need to subtract in the opposite order.

I don't understand what you mean, can you please explain?
 
  • #7
Evangeline101 said:
I tried doing it this way, but as you said there is no real solution.

I don't understand what you mean, can you please explain?
If x > 200, then
##\displaystyle \frac{4800}{x-200}>\frac{4800}{x}##​
.
So you had these reversed.
 
  • #8
SammyS said:
If x > 200, then
4800x−200>4800x4800x−200>4800x\displaystyle \frac{4800}{x-200}>\frac{4800}{x}.
So you had these reversed.

So even if I switch these two, can I not get the same answer I had originally? How does switching the two help with the answer to the problem? or is it just the proper way to write it?
 
  • #9
Evangeline101 said:
So even if I switch these two, can I not get the same answer I had originally? How does switching the two help with the answer to the problem? or is it just the proper way to write it?
It's what is needed of you want to make everything consistent.

As I stated in my first reply, the answer you gave for the time from Bangkok to Tokyo was correct. (600 km/hr)

But you had a number of inconsistencies.

Added in Edit:
You should get x = 800. Then x- 200 = 600, the answer.
 
Last edited:
  • #10
SammyS said:
It's what is needed of you want to make everything consistent.

As I stated in my first reply, the answer you gave for the time from Bangkok to Tokyo was correct. (600 km/hr)

But you had a number of inconsistencies.

Added in Edit:
You should get x = 800. Then x- 200 = 600, the answer.

So like this:

upload_2016-5-23_20-55-12.png
 
  • #11
Evangeline101 said:
So like this:

View attachment 101169
No.Not like that.
The first three lines are correct.

After that, there are at least two Algebra mistakes.

As I stated in my previous post:
SammyS said:
You should get x = 800. Then x- 200 = 600, the answer.
 
  • #12
This is an example from my lesson that I have been using as a reference to solve my problem:
upload_2016-5-24_0-49-22.png


upload_2016-5-24_0-49-45.png
 
  • #13
Evangeline101 said:
This is an example from my lesson that I have been using as a reference to solve my problem:
View attachment 101173

View attachment 101174
Right. And they did not make algebra mistakes. You did.

So (carefully) redo your algebra, starting at the third line of the following (from post #10), which is the last line that's correct.

upload_2016-5-23_20-55-12-png.101169.png
 
  • #14
SammyS said:
No.Not like that.
The first three lines are correct.

After that, there are at least two Algebra mistakes.
upload_2016-5-24_1-23-4.png
4800x - 4800x + 960 000 = 2x2 - 400x (960 000 is positive because I multiplied -4800 and -200)

960 000 = 2x2 - 400x (Now I move 960 000 to the right side and it becomes -960 000)

2x2 - 400x - 960 000 = 0

x2 - 200x - 480 000 = 0

(x+600) (x-800)

x= -600 or x = 800

Does this make more sense? did I fix the algebra errors? if not please show me where I made errors.
 

Attachments

  • upload_2016-5-24_1-22-38.png
    upload_2016-5-24_1-22-38.png
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  • #15
Evangeline101 said:
View attachment 1011774800x - 4800x + 960 000 = 2x2 - 400x (960 000 is positive because I multiplied -4800 and -200)

960 000 = 2x2 - 400x (Now I move 960 000 to the right side and it becomes -960 000)

2x2 - 400x - 960 000 = 0

x2 - 200x - 480 000 = 0

(x+600) (x-800) = 0

x= -600 or x = 800

Does this make more sense? did I fix the algebra errors? if not please show me where I made errors.
Yes. That looks to be correct.
 
  • #16
Okay, so does that make the speed from Bangkok to Tokyo 800 km/h instead of 600 km/h since it is positive?
 
  • #17
SammyS said:
You should get x = 800. Then x- 200 = 600, the answer.

So since x = 800, we need to solve for the jets's speed from Bangkok to Tokyo, so (like you said) sub x = 800 into x- 200, which gives:
800 - 200 = 600 km/h

So the jet's speed from Bangkok to Tokyo is 600 km/h.
 
  • Like
Likes SammyS
  • #18
Thanks for the help, I really appreciate it :)
 

Related to Application of Quadratic Functions that involve finding equation

1. What is a quadratic function?

A quadratic function is a type of mathematical function that can be written in the form f(x) = ax^2 + bx + c, where a, b, and c are constants and x is the independent variable. It is a polynomial function of degree 2, meaning the highest power of x is 2.

2. How do I find the equation of a quadratic function?

To find the equation of a quadratic function, you need to know three key points on the graph of the function. These points can be in the form of coordinates (x, y). Once you have these points, you can use the point-slope form or the standard form of a quadratic equation to find the equation. Alternatively, if you know the vertex and one other point, you can use the vertex form to find the equation.

3. What is the vertex of a quadratic function?

The vertex of a quadratic function is the highest or lowest point on the graph of the function. It is also the point where the function changes direction from increasing to decreasing or vice versa. The x-coordinate of the vertex can be found by using the formula x = -b/2a, and the y-coordinate can be found by substituting the x-coordinate into the function.

4. Can a quadratic function have more than one x-intercept?

Yes, a quadratic function can have zero, one, or two x-intercepts. The number of x-intercepts depends on the discriminant of the quadratic equation, which is b^2 - 4ac. If the discriminant is greater than zero, the function will have two x-intercepts. If it is equal to zero, the function will have one x-intercept. And if it is less than zero, the function will have no x-intercepts.

5. How can I use quadratic functions in real-life applications?

Quadratic functions have many real-life applications, such as in physics, engineering, and economics. They can be used to model the trajectory of a projectile, the shape of a parabolic mirror, or the profit and cost functions of a business. They can also be used to solve optimization problems, such as finding the maximum or minimum value of a quantity.

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