Accounting for Liquid Water Density in Ideal Gas Pressure Calculations

In summary: What is the result of the calculation?The result of the calculation is that the partial pressure of dry air at 1 atm is 0.3375 bar.
  • #1
dbag123
76
3
Homework Statement
in a jar that has an airtight lid there is water. Temperature is raised to 120C, and as a result the pressure of the water vapor is 1,99bar. Calculate the partial pressure of dry air and the total pressure.
Relevant Equations
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First calculate the total pressure, but that gives me p2=p1*t2/t1 = 2,86 bar and partial pressure of 0,87 bar which is wrong. any tips?
 
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  • #2
what about using the polytropic process to figure out the partial pressure of the dry air at 1 atm?, the increase would be 0.3375 bar and that is the right answer, initial temperature is 90C
 
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  • #3
dbag123 said:
what about using the polytropic process to figure out the partial pressure of the dry air at 1 atm?, the increase would be 0.3375 bar and that is the right answer, initial temperature is 90C
Why do you need to use a polytropic process? This is an equilibrium problem.

What is the exact word-for-word statement of the problem?
 
  • #4
in a jar that has an airtight lid there is water. Temperature is raised to 120C, from 90C, where the pressure of water vapor is 0,7 bar and the air 1 atm and as a result the pressure of the water vapor is 1,99bar. Calculate the partial pressure of dry air and the total pressure.
 
  • #5
Makes a difference ! What happens to the 1 atm when going from 90 to 120 C ?
 
  • #6
dbag123 said:
in a jar that has an airtight lid there is water. Temperature is raised to 120C, from 90C, where the pressure of water vapor is 0,7 bar and the air 1 atm and as a result the pressure of the water vapor is 1,99bar. Calculate the partial pressure of dry air and the total pressure.
You need to assume that the change in the volume of liquid water is negligible.
 
  • #7
Chestermiller said:
You need to assume that the change in the volume of liquid water is negligible.
One could account for the density of the liquid water. However, since liquid water is approximately 1000 times as dense as steam at 2.0 bars, one might expect such an accounting to affect the result only in the third significant digit. The inputs here look to be good to only two digits at best.
 

Related to Accounting for Liquid Water Density in Ideal Gas Pressure Calculations

1. What is an ideal gas pressure problem?

An ideal gas pressure problem is a type of physics or chemistry problem that involves calculating the pressure of an ideal gas in a given situation. This type of problem typically involves using the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas.

2. What is the ideal gas law?

The ideal gas law is a mathematical equation that describes the behavior of ideal gases. It is written as PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

3. How do you solve an ideal gas pressure problem?

To solve an ideal gas pressure problem, you will need to use the ideal gas law and rearrange it to solve for the pressure (P). First, make sure all units are in the correct form (pressure in Pa, volume in m^3, temperature in K). Then, plug in the known values and solve for the unknown value (pressure).

4. What are the units for pressure in ideal gas problems?

The units for pressure in ideal gas problems are typically in Pascals (Pa). However, this can vary depending on the units used for volume and temperature in the problem. It is important to make sure all units are consistent when solving ideal gas problems.

5. What are the assumptions made in ideal gas pressure problems?

The main assumptions made in ideal gas pressure problems are that the gas behaves ideally (following the ideal gas law), and that there are no intermolecular forces between gas particles. Additionally, the gas is assumed to be in a closed system and at a constant temperature.

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