1. solve the equation
3x^(-1/2) - 4 = 0

2. I've moved this thread here to our algebra forum since this is a better fit given the question.

We are given to solve:

$\displaystyle 3x^{-\frac{1}{2}}-4=0$

What do we get if we multiply through by $x^{\frac{1}{2}}\ne0$?

Originally Posted by MarkFL
I've moved this thread here to our algebra forum since this is a better fit given the question.

We are given to solve:

$\displaystyle 3x^{-\frac{1}{2}}-4=0$

What do we get if we multiply through by $x^{\frac{1}{2}}\ne0$?
i don't get it?

4. Originally Posted by Dil
i don't get it?
Well if we multiply through by $x^{\frac{1}{2}}$ we have:

$\displaystyle 3x^{-\frac{1}{2}}x^{\frac{1}{2}}-4x^{\frac{1}{2}}=0x^{\frac{1}{2}}$

Now, for the first term on the left, we can use the following property of exponents:

$\displaystyle a^{b}\cdot a^{c}=a^{b+c}$

So, what does this term become?