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Thread: Indices

  1. MHB Apprentice

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    #1
    solve the equation
    3x^(-1/2) - 4 = 0

  2. Pessimist Singularitarian
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    #2
    I've moved this thread here to our algebra forum since this is a better fit given the question.

    We are given to solve:

    $ \displaystyle 3x^{-\frac{1}{2}}-4=0$

    What do we get if we multiply through by $x^{\frac{1}{2}}\ne0$?

  3. MHB Apprentice

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    #3 Thread Author
    Quote Originally Posted by MarkFL View Post
    I've moved this thread here to our algebra forum since this is a better fit given the question.

    We are given to solve:

    $ \displaystyle 3x^{-\frac{1}{2}}-4=0$

    What do we get if we multiply through by $x^{\frac{1}{2}}\ne0$?
    i don't get it?

  4. Pessimist Singularitarian
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    #4
    Quote Originally Posted by Dil View Post
    i don't get it?
    Well if we multiply through by $x^{\frac{1}{2}}$ we have:

    $ \displaystyle 3x^{-\frac{1}{2}}x^{\frac{1}{2}}-4x^{\frac{1}{2}}=0x^{\frac{1}{2}}$

    Now, for the first term on the left, we can use the following property of exponents:

    $ \displaystyle a^{b}\cdot a^{c}=a^{b+c}$

    So, what does this term become?

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