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  1. MHB Craftsman

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    #1
    The students in a hostel are to get new uniforms. Each girl is to receive a blouse and a skirt , each boy is to receive a shirt and a pair of trousers.1 meter of white material is required to sew a blouse and $1\frac{1}{2}$ meters of blue material is required to sew a shirt . Moreover $1\frac{1}{2}$ meters of blue material is required to sew a skirt and 2 meters of blue material is required to sew a pair of trousers. The total amount of white material is 72 meters and the total amount of blue material required is 100 meters.

    i.Taking the number of girls as $x$ and the number of boys as $y$ , construct a pair of simultaneous equations in x and y

    I need help in constructing the pair of equations.

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    #2
    Quote Originally Posted by mathlearn View Post
    The students in a hostel are to get new uniforms. Each girl is to receive a blouse and a skirt , each boy is to receive a shirt and a pair of trousers.1 meter of white material is required to sew a blouse and $1\frac{1}{2}$ meters of blue material is required to sew a shirt . Moreover $1\frac{1}{2}$ meters of blue material is required to sew a skirt and 2 meters of blue material is required to sew a pair of trousers. The total amount of white material is 72 meters and the total amount of blue material required is 100 meters.

    i.Taking the number of girls as $x$ and the number of boys as $y$ , construct a pair of simultaneous equations in x and y

    I need help in constructing the pair of equations.
    Hey mathlearn,

    Did you already try something? Or can you explain where you're stuck?

    With $x$ girls, how many blouses and skirts will we need?
    How much of the materials will that require?

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    Quote Originally Posted by I like Serena View Post
    Hey mathlearn,

    Did you already try something? Or can you explain where you're stuck?

    With $x$ girls, how many blouses and skirts will we need?
    How much of the materials will that require?
    Hey I like Serena ,

    I was totally helpless here & that Implies that I am stuck in the beginning.

    With $x$ girls 1m*$x$ for blouse & $1\frac{1}{2}$ meters for skirt

    Taking boys as $y 1\frac{1}{2}$ for shirt and 2 of the blue material for trousers.

    I will attempt to construct a pair of simultaneous equations.

    $1x+1\frac{1}{2}y=72m\left(white material\right)$

    $1\frac{1}{2}x+2y=100m\left(blue material\right)$

    You have forgot to wink ('') here

    Quote Originally Posted by I like Serena View Post
    Hey mathlearn,

    Did you already try something?

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    #4
    Quote Originally Posted by mathlearn View Post
    Hey I like Serena ,

    I was totally helpless here & that Implies that I am stuck in the beginning.

    With $x$ girls 1m*$x$ for blouse & $1\frac{1}{2}$ meters for skirt

    Taking boys as $y 1\frac{1}{2}$ for shirt and 2 of the blue material for trousers.

    I will attempt to construct a pair of simultaneous equations.

    $1x+1\frac{1}{2}y=72m\left(white material\right)$

    $1\frac{1}{2}x+2y=100m\left(blue material\right)$

    You have forgot to wink ('') here
    There you go!
    Except that boys are fully clad in blue, so it should be:

    $1x=72\text{ m (white material)}$

    $1\frac{1}{2}x++1\frac{1}{2}y + 2y=100\text{ m (blue material)}$

    Looks like we might run short on blue material!

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