Recent content by zan123_

does this work? vf^2=vi^2 + 2ad 0 = 12.3^2 +2(9.8)d 0 = 151.29 + 19.6d d = 15129/19.6 d=7.7 m

thank you so much for your help! I was talking about the answer in the original post

oh okay, i have learned equations but i have a hard time applying them in word questions like these. we dont have a lot of problems to practise so i've been having trouble. Since I have the velocity would i do: Ek=1/2mv^2 = 1/2(5)(12.3)^2 Ek=378.225 J Eg=mgh =(5)(9.8)(4) 196 J Emech=ek+eg...

could you clarify what do you mean? it is on a 5 kg cart moving down a 4 m ramp. i don't know what equations i should use to calculate this

is the answer above correct? and is there any way someone can clarify why/how Work done is 1/2mv^2. It is not clear for me thank you.

the wheels dont get stuck, there is not clarification for that in the question