Couldn't you just resolve the horizontal velocity as ##v\cos(\theta)## and the vertical velocity as ##v\sin(\theta)##, and solve the differential equation for both to find x(t) and y(t)? If you were to resolve the forces as well, the ##F_{air}## in the vertical direction would be...
That makes so much more sense. I never really understood the negative sign on -bv until now, so thank you so much for clearing that up, and thank you to PeroK for offering a valuable insight onto the problem :smile:
Got it, one more question - doesn't the direction of the force due to air resistance change after the projectile reaches its maximum height? As the projectile is ascending and descending, the force due to air resistance changes direction as it opposes the direction of motion.
If so, how would...
Oh that makes sense. Does that mean I would take the integral of the acceleration found from the free body diagram to get v(t), and then take the integral of that to find x(t)?
Mentor note: Moved from a technical forum section, so Homework Template is not present.
Hello Physics Forums members,
I am a student in AP Physics C and I was just working out the range of a projectile when air resistance is non-negligible. As of right now I'm going to use the linear model of...