Hello MindZiper,
This post was made months ago so I thank you for reminding me of it.
I think I can provide the correct answer - in fact I've noticed some mistakes I made previously so to clarify I will write it step by step. Firstly something important:
We must find the magnitude of the...
Okay here's the next step.
\frac{kQ^2}{l^2}\left[\frac{-l\hat{i}-l\hat{j}-l\hat{k}}{l}\right]
+\frac{kQ^2}{2l^2}\left[\frac{-2l\hat{i}-2l\hat{j}-2l\hat{k}}{\sqrt{2}l}\right]
+\frac{kQ^2}{3l^2}\left[\frac{-l\hat{i}-l\hat{j}-l\hat{k}}{\sqrt{3}l}\right]
I don't know how to add them to...
Is this the sum of the individual force components (the vectors are in brackets)?
\frac{kQ^2}{l^2}\left[\frac{-l\hat{i}}{l}\right]+\frac{kQ^2}{l^2}\left[\frac{-l\hat{j}}{l}\right]+\frac{kQ^2}{l^2}\left[\frac{-l\hat{k}}{l}\right]...
I have also put the charges along the axis as you have described. So the vector caused by each charge:
(1,0,0) \ \ a_1 = -l\hat{i}
(0,1,0) \ \ a_2 = -l\hat{j}
(0,0,1) \ \ a_3 = -l\hat{k}
(1,1,0) \ \ a_4 = -l\hat{i}-l\hat{j}
(0,1,1) \ \ a_5 = -l\hat{j}-l\hat{k}
(1,0,1) \ \ a_6 =...
Hi, thanks for your response. I'm not sure where I can get the 3.69 value. The resultant vector is 4l\hat{i}+4l\hat{j}+4l\hat{k}.
F = \frac{Q^2}{4\pi\epsilon_0R^2}\cdot\hat{a}
Is R the magnitude of the resultant vector - it would be \sqrt{48l^2}?
I think I'm getting confused.
Hello, I'm having a little trouble with this:
Coulomb Force Point Charges on Cube
Homework Statement
Identical charges of Q (C) are located at the eight corners of a cube with side L (m). Show that the coulomb force on each charge has magnitude:
3.29Q^2/4\pi\epsilon_0l^2
Homework Equations...