ok - it will go to 2 then?
\frac{log (e^{2x})}{x + 3} \leq \frac{log (x^{2} + e^{2x})}{x + 3}
\leq ?
\frac{log (e^{2x})}{x + 3} = \frac{2x}{x + 3} which tends to 2 as x tends to infinity is this correct - what should i use for thew upper bound?
Homework Statement
\frac{log (x^{2} + e^{2x})}{x + 3} find the limit as x_> infinty
Homework Equations
powers beat logs
The Attempt at a Solution
going by the powers beat logs idea - simply, the limit as n-> infinity is 0.
is this correct? can you simply say that powers beat logs always?
Homework Statement
im being asked for the first 4 non zero values for the taylor expansion of exp(x) which is simple, but then it asks for the range of x values that are valid for the expansion.
i have never come across ths before - any idea?