Yes, it would work anywhere. Basically, if you were in some vehicle that was traveling in a circle with a radius equal to the distance from the center of any given mass at a radial velocity equal to the escape velocity from that mass at that height, the net acceleration would be equal to the...
Yes, there is a difference between what a net force on you would be (and by extension, acceleration) and the pressure. Imagine that you are between two solid iron walls and each wall is exerting a force on you of some arbitrarily high amount. A million tons each, let's say. The net force on...
This is just a reality that I have stumbled upon that I'm sure was well-known, but I still found it interesting. I apologize if this is second-nature to physics experts.
I was responding to a post on a different thread that claimed you could make a tunnel around the Earth and if you sent a...
I added it, but it doesn't do much. The "dry mass" of just 1 kg is virtually zero almost the entire time (until the very end long after the issue I have a question about) and the "remaining fuel" line is virtually identical to the total remaining since it's just the total minus the line that is...
Yes, that's what I did. There are two lines in the graph that make like a fish shape. These are the two independent momentum values for each the rocket and fuel. Obviously, the sum of which is zero the entire time. Arbitrarily, the rocket's momentum is the negative value; fuel is positive...
I would like to preface this by saying that I do not in any way resemble a physicist - and I'm sure the crudeness of my work will confirm that, but I thought that this was so cool, I wanted to share it. I'm just a follower of physics.
I understand that some of the concepts I'm going to be...
The explanation as to why galaxies like the Milky Way and Andromeda are not expanding away from each other is that they are gravitationally bound, and the expansion at that small scale is not really apparent anyway. My question is purely hypothetical. What if you had a measuring stick that...
Please correct me if I am wrong. I can look at this from two different angles. One being that special relativity is specific to inertial reference frames and neither rotating along with the surface of the Earth nor standing at the pole spinning opposite the Earth's rotation are inertial...
Here is an example of what I am talking about :
Just so I don't get outrageous with the masses here, I looked up the largest known black holes. The largest I could find was one that is 23 billion times the mass of the sun. Please - anyone correct my mistakes. The Schwartzchild radius of a...
Nugatory - I really appreciate your response. I willingly admit that I am beyond undereducated in this area, but I do understand your explanations. Thank you for taking the time. I've never taken a physics course officially other than basics in high school; I'm just thoroughly interested in...
According to Newtonian physics, can't super-massive black holes have relatively mild proper accelerations at the event horizon? I understand that saying "according to Newtonian physics" pretty much is meaningless within the realm of black holes, but this is why I am asking. I understand that I...
Let me clarify that I am not attempting to make a case that you could exit from within a black hole in a machine under power. I understand that it is not possible; I wanted an explanation as to why. Yours makes sense, and I understood this much already.
It is my understanding that at the most fundamental level, a black hole is simply an object with a gravitational field so strong that there exists a sphere that lies outside the body of mass of that object from which the escape velocity is equal to the speed of light. In other words, a body of...
I'm sure it does 'need' those digits. I regret making that comment. I said 'rarely' needed. Not 'never' needed, and as I've explained to others, In the spirit of my argument, 15 digits still makes my point. Pi has been calculated to 5 TRILLION digits. THAT is what I mean when I say there is...