Recent content by Trentkg

Ah yes! Of course, how simple. Thank you erland!

M = X^-1 (P*K)X so you're saying X^-1 (P*K)X = (P*K)X^-1 *X ? My Linear algbra is a little rusty, but isn't matrix multiplication not communative?

This question broadly relates to principle component analysis (PCA) Say you have some data vector X, and a linear transformation K that maps X to some new data vector Z: K*X → Z Now say you have another linear transformation P that maps Z to a new data vector Y: P*Z → Y is there...