if at R2 , we have
8volts = 2 ohm *i
and i isolate i , then i=4
i = 8 / 2 +6 , so i = 1 amp after R3
where are you going with this, i tought we needed to calculate the equivalent resitance value for the entire circuit , then isolate for the last one , using the total...
god, i had the right answer all along, and been trying for 3 days to understand people explaining to me the incorrect answer
so apparently i was right all along folks, should of trusted my judgement first
(2*10^-2) N / 1000metre= ((4π*10^-7) i ^2 ) / 2π *1 or * 0.5 ) since distance between the wire is 1 metre . so diameter is 1 meter , r should be half that, so 0.5
so if r =1 and L = 1000 meters ---> i = 10 amps
if r=1 and no value for L then i = 316 amps
if r= 0.5...
1/0 doesn't exist . having cos 90 at denominateur will make the entiere fraction divided by 0 . even then , it would mean C would be the answer which it isn't , and since it isn't D . it has to be A.
sin 90 = 1
cos 90 = 0 , so 1/0 no good
from 0 to pi ,( 0 to 180 ) mouvement is upwards and from pi to 2 pi, goes downward...? ? hmmm
wait , cos 180 is -1 , sin 180 is 0
from 0 to 90 , sine increases, , cosine decreases
and from 90 to 180 , since decreases, cosine increases
amp meter reads 2 amps , after the unknow resistance . which is the same junction after R3 .
as you can see from the arrows , initial guess for the current flow , suggest that after R2 , current would go on through R3 , then R1 and then to the battery
R2 and R3 are in series , so their...
well the problem stated here is quite vague , and here are the formulas found in the book, for a force between 2 parallele current can either be attractive or repulsive depending if the current is oriented in the same direction . So i gather the amount of force is the same , with only the...