Recent content by tandennis0703

The velocities at C and D are the same. The conveyor is the one that is moving at 6 and 2 ms-1 respectively. Therefore I am not able to find the normal acceleration by using the velocities of the conveyor belt. The velocities at B,C, and D of the wheel are constant, so I can use either...

Oh no I did not see the question correctly. Both the velocity at C and D of the WHEEL is the same. It is the side belt that's moving at a velocity.

My maths is fine. I have the answer which is w=16. To get w you need to equate both VD and VC by using the radius r as the IC point. Vd=wx ; 6=wx Vc=w(0.5-x) ; 2=w(0.5-x) Therefore by substitution, you get the angular velocity equals to 16 ms-1. I hope this helps you...

Homework Statement Hi, I was wondering what is the difference between the equations an=w^2 x R vs an=V^2 / R? I thought both of these equations were the same? What is the normal acceleration at C and D? Homework Equations an=w^2 x R vs an=V^2 / R? The Attempt at a Solution [/B] If I use...

Thanks for the reply. However I am still a bit confused as to how I know whether or not a bar is undergoing compression or tension. Do I need my calculations in order to figure that out?

Joint A: +^ΣFy=0 ; -2P+(2/3.61)FAB=0 FAB=3.61P >+ ΣFx=0; -FAE+(3/3.61)(3.61)P=0 FAE=3P Joint E: +^ΣFy=0; FEB-P=0 FEB=P >+ ΣFx=0; 3P - FED=0 FED=3P Joint B: +^ΣFy=0; (2/3.61)FBD-P-(2/3.61)(3.61)(P)=0 (2/3.61)FBD=3P FBD=5.415P >+ΣFx=0; FBC -(5.415)(3/3.61)(P)-(3.61)(P)(3/3.61)=0 FBC=7.5P...

Sorry for the mistakes. I never took statics in my course. I redid everything and used the method of summing the resultant forces in both the x and y direction. I am still a bit confused as to how to figure out whether or not it is a compression/ tension force. Hopefully my calculations are correct.

Homework Statement Homework Equations The Attempt at a Solution I have spent the last 2 hours trying to figure out which part of the truss is compression or tension. Hopefully the second screenshot I took is correct. I tried figuring out the first few parts, just want to make sure that at...