Homework Statement
Derive Newton's and Lagrange's equation of motion for the system. Discuss differences and show how Newton's equations can be reduced to lagrange's equations. Assume arbitrarily large θ.
The system is a pendulum consisting of a massless rod of length L with a mass m...
I am working on this same problem but need to compare the lagrange solution to the Newtonian solution. I am stuck on summing the forces and moments of the problem, anyone have any ideas?
Hmm interesting video but I am afraid something is just not clicking for me with regards to this problem.
for the potential energy there will be a m1gy1 term and a m2gy2 term. I assume there must also be terms for the work done by the tension in the strings, but only the y components as these...
Homework Statement
Derive the equation of motion for the system in figure 6.4 using Lagrange's equations
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Homework Equations
m1=.5m
m2=m
strings are massless and in constant tension
Lagrange=T-V
The Attempt at a Solution
I currently have the kinetic energy as .5m1y'12 + .5m2y'22
I am...
Homework Statement
Derive Newton's and Lagrange's equation of motion for the system. Discuss differences and show how Newton's equations can be reduced to lagrange's equations. Assume arbitrarily large θ.
The system is a pendulum consisting of a massless rod of length L with a mass m...
wheni apply the boundary conditions i find that B=0 and therefore am left with Psi(x) = A\ Sin(\sqrt{\frac{2mE}{\hbar^2}}x), by a natural number do you mean e? because i had seen before that Psi(x) = A\ Sin(\sqrt{\frac{2mE}{\hbar^2}}x) can turn into some function Psi(x) = Ae^someting but i do...
with A solved for and pulgged back in the function is now normalized, so the next part of the question asks me to find the possible results of measures of the energy and what are the respective probabilities of obtaining each result
to normalize it it has to be set equal to 1 and we need to find A, also to fix my integral above, i did it out wrong and it is actualy equal to A^2 +(19/20) so that means if i set it equal to 1 that A = \sqrt{1/20}