I'm not sure. My answer was marked incorrect which is strange. I understand the problem and how to do it. I figured maybe my work was wrong or a small error?
1. Question
The speed of an electron is known to be between 6.0×10^6 m/s and 6.7×10^6 m/s . Estimate the uncertainty in its position.
Homework Equations
ΔpΔx ≥ h/2π
(mΔv) Δx ≥ h/2π (Since Δp= mΔv)
Δx≥ h/2π(mΔv)
h= 6.63*10-34 J*s
c= 3.0*108
mass of electron= 9.11*10-31
The Attempt at a...
I am doing a lab experiment with regard to combined circuits, and I wanted to check my data to see if I made an error in my experiment.
Theoretically speaking, in a combined circuit, should Itotal (total current) be equivalent to the Imeasured value?
I calculated my Itotal to be .0292A since...
I have voltage, diameter, area, and inverse area data values. How could I calculate the resistance and resistivity with these numbers? I am pretty sure resistance is R=V/I and resistivity= RA/L , so I am not sure how I can calculate resistance without an I value.
Homework Statement
Six forces, each of magnitude either F or 2F, are applied to a door as seen from above in the figure.
Rank in order, from smallest to largest, the six torques τ1to τ6 about the hinge.
Homework Equations
torque=RFsintheta
The Attempt at a Solution
τ1 = F*L/2
τ2 = 2F*L/4
τ3 =...
5.67pi ...i don't understand why I keep getting a wrong answer from my calculator. Thanks. So 5.67
(5.67^2)/.400
=80.37
sqrt( (80.37^2)+(.361^2) )
=80.37
? this ok now?
Based on my original post, which step did I mess up
centripetal acceleration = (v*v)/r
I calculated v (tangential velocity) to be 1.11 ---which is correct based on answer key
= (1.11^2)/.400
=3.08
α =
−8
radians/s2
ANSWER 2: Deduction: -3%
α =
−8π3
radians/s2
The question only asks for the magnitude of the angular acceleration.
ANSWER 3: Deduction: -3%
α =
−8.4
radians/s2
The question only asks for the magnitude of the angular acceleration.
ANSWER 4: Deduction: -3%
α =
−2.67π...