And, if you ask me, this is one of the great thibgs about science. Scientists are willing (generally) to revise what they know ...to say "Ok, I know a bit more information now, so that means what I thought was right before has changed a bit".
I wonder would your philosophy teacher be so open...
Hello.
I was womdering does anyone know any good resources of information on Fermi level de-pinning & Schottky barriers?
I have been hunting around online, with not much luck. I thought someone here might be able to suggest some things.
Thanks.
Seán
Yes, two. One, I am a bit of an idiot, and two, I should have been asleep hours ago! Sorry about that :redface:
Yes, I think I have it now.
Thanks for everyones help! And I shall make sure I read over what I have written before I submit it in future!
Again, many thanks.
Seán
Hello, thanks for the reply!
Right, am I right in saying that the de^(x-d)-(x-d) comes to e^0 = 1?
But the why is the other other exponential all over d, and not d - d?
Thanks.
Seán
Hello.
Sorry, there was a typo, the second line should have been
\frac{d}{D_pB}\int e^{x/d}(-de^{-W_B/d} + de^{-x/d}) dx
Working out the brackets, I get
e^{x/d}(-de^{-W_B/d} + de^{-x/d}) dx
goes to (I think)
-de^{x-W_B/d} + de^{d}
I am not sure about the de^d part.
Seán
Hello.
I am going through some worked examples for a class I have, and there is one step I don't understand, and I hope someone can help me with that.
It goes from
\frac{1}{D_pB}\int e^{x/d}(-de^{-W_B/d} + de^{-x/d}) dx
to
\frac{1}{D_pB}\int (1 - e^{x-W_B/d}) dx
The limits are...
Hello,
Rather than start another topic, since this question is related to this tread, I thought I would just tack it on here.
We were asked to "Derive a formula for the output signal y as a function of t". I think I have done this correctly, but would be very grateful if someone could cast...
Well, the online reference I used to make sure said d/dt sin x = cos x.
So, I was taking x = wt.
Anyway, that is neither here nor there. Again, thank you for all your help, and I will check out that book you mentioned.
Seán
Hello,
Well, differentiating a constant is zero, but I am not sure of that holds for 0. And differentiating sin(wt) would be cos(wt).
I have done a course in electrical circuits, but it is all very rusty, and very much from a hands on point of view.
Seán
So, if I have it right, it should be
y'(t) + 2y(t) = x(t)?
Yea, that would be great! I really want to learn as much as I can!
And again, thanks so much for all your help. Hopefully (if I finally have it right) I will be able to do it myself.
Seán