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• Today, 21:33
The region $R$ is a rectangle having the vertices: (0,1),\,(1,1),\,(1,-1),\,(0,-1) One way we can compute the volume is: ...
4 replies | 53 view(s)
• Today, 19:41
MarkFL replied to a thread logs in Pre-Algebra and Algebra
Okay, we are given: \ln\left(x-\frac{1}{x}-3\right)=2 Converting from logarithmic to exponential form, we have: x-\frac{1}{x}-3=e^2 ...
1 replies | 15 view(s)
• Today, 15:26
As for the $\LaTeX$, look under the "Calculus/Analysis" section of our Quick $\LaTeX$ tool. You will find it, which gives the code: ...
4 replies | 53 view(s)
• Today, 10:48
MarkFL replied to a thread The Fonz and Geometry in Chat Room
Yes, and I was just pointing out that there can be other reasons a student fails besides lack of innate ability to understand the material, or an...
5 replies | 63 view(s)
• Today, 10:18
MarkFL replied to a thread The Fonz and Geometry in Chat Room
If a child's parents consistently put a child down, then I think this can have negative consequences on the child. I think there are a great many...
5 replies | 63 view(s)
• Yesterday, 23:08
I disagree with this...I think it is the societal attitude that it's okay to fail at math that is part of the problem. Someone says to their friends,...
9 replies | 94 view(s)
• Yesterday, 22:23
If we have 2000 people, 300 of which are women, then the probability that all 300 women will be on the same team is given by: P(A)=\frac{{1700...
5 replies | 51 view(s)
• Yesterday, 22:01
I think your second method is correct. Suppose we call the teams $X$ and $Y$...and now we need only look at one team, so let's look at team $X$. If...
5 replies | 51 view(s)
• Yesterday, 19:04
MarkFL replied to a thread Solar Eclipse 2017 in Chat Room
Yesterday during the big event, we had pervasive heavy cloud cover and intermittent rain. Today, sunny and clear all day. Story of my life...(Giggle)
8 replies | 233 view(s)
• Yesterday, 03:58
Suppose that $z_n\leqslant1$. Then $z_n^2 \leqslant z_n \leqslant 1$, $z_n^3 \leqslant z_n^2 \leqslant 1$, ... , and by induction $z_n^k\leqslant 1$...
4 replies | 70 view(s)
• August 21st, 2017, 11:54
If $c>1$ then $c^n < c^{n+1}$. Raise both sides to the power $\frac1{n(n+1)}$ to get $c^{1/(n+1)} < c^{1/n}$. In other words, $z_{n+1} < z_n.$
4 replies | 70 view(s)
• August 20th, 2017, 01:29
MarkFL posted a visitor message on Peter's profile
Hey Peter! (Wave) I edited your post to remove the duplicate content. Sorry for the late reply, I was busy "powering through" a tedious 3 hour...
• August 17th, 2017, 06:02
Yes! (Yes)
4 replies | 77 view(s)
• August 17th, 2017, 02:10
Small quibble...axis of symmetry is: t=-\frac{1}{105} So, since the parabola opens up, the vertex is a minimum, so the minimum distance will be...
8 replies | 174 view(s)
• August 17th, 2017, 00:59
For a parabola of the form: f(x)=ax^2+bx+c We know the axis of symmetry is at: x=-\frac{b}{2a} So, for:
8 replies | 174 view(s)
• August 16th, 2017, 22:42
Overview: This product is designed to auto-post a welcome thread for all new users once they have completed all verifications, and/or returning...
0 replies | 28 view(s)
• August 16th, 2017, 21:58
Isn't this question a duplicate of the following? 231.12.3.65 Determine the smallest distance between a point and a line
1 replies | 45 view(s)
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