• Today, 02:08
Okay, to construct the dynamic tangent line graph for this function, we begin with the point: (a,a^2+3a) and the slope: 2a+3 And we...
10 replies | 158 view(s)
• Yesterday, 23:22
What contest is this for? Currently there is another Kaggle competition on predicting house prices in the Russian housing market. I have done a...
4 replies | 124 view(s)
• Yesterday, 19:45
The area over which we are integrating is the upper half of the circle centered at $(1,0)$, which is described in polar coordinates by: ...
1 replies | 20 view(s)
• Yesterday, 19:08
Yes, in my previous post, I used in the graph the fact that at the point $(a,a^3)$ on the curve, the slope of the tangent line will be $3a^2$. So,...
10 replies | 158 view(s)
• Yesterday, 14:51
There is an error in the working by first principles, because if given: f(x)=x^3 then: f'(x)=3x^2 What this means is that for any value...
10 replies | 158 view(s)
• Yesterday, 11:16
Hi kupid, (Wave) I'll try my best to cover the first part of your questions. These are good things to ask by the way! There is a precise...
10 replies | 158 view(s)
• Yesterday, 08:56
Notice that x= \sqrt{4^2- y^2} is the right semi-circle of the circle x^2+ y^2= 4, the circle with center at (0, 0) and radius 2. Restricting y to...
5 replies | 78 view(s)
• April 28th, 2017, 21:54
Okay, our first step is to transform the iterated integral into a double integral: I=\int_0^a...
5 replies | 78 view(s)
• April 28th, 2017, 21:21
MarkFL replied to a thread Stay on Course in Geometry
Looks good to me. (Yes)
3 replies | 59 view(s)
• April 28th, 2017, 19:33
MarkFL replied to a thread Stay on Course in Geometry
The first leg of Ima's journey lies along the line passing through the origin, with slope -1...so using the point-slope formula can you determine the...
3 replies | 59 view(s)
• April 28th, 2017, 19:20
What we have is: I=\int_0^a y\int_0^{\sqrt{a^2-y^2}}\,dx\,dy Evaluating the inner integral, we obtain: I=\int_0^a...
5 replies | 78 view(s)
• April 28th, 2017, 10:38
Since $g(x) = f(x) - \frac12x$, it follows that $g(1) = \frac12$, $g(2) = 2$ and $g(3) = \frac32$. But $\frac12<\frac32<2$, so by the intermediate...
9 replies | 168 view(s)
• April 28th, 2017, 08:14
In the original post we are told that the region is "the semicircle bounded by y = {4 - x^2}, y = 0". But that is not a semi-circle, it is a...
5 replies | 125 view(s)
• April 28th, 2017, 03:44
That's where the intermediate value theorem comes in. Use it to show that there is a point $d$ between $1$ and $2$ at which $g(d) = g(3)$. Then you...
9 replies | 168 view(s)
• April 28th, 2017, 00:29
MarkFL posted a visitor message on MoreCoffee's profile
Hey Phil! (Wave) Yeah...I got tired of the same as well as other issues. Just decided it was best to part ways with CH. :D
• April 27th, 2017, 21:07
I'm thinking that perhaps what was intended was that the coordinates of the 3 vertices would all be integers. :)
3 replies | 81 view(s)
• April 27th, 2017, 19:24
I think I would convert to Cartesian coordinates: L1\implies x+5y=7 L2\implies x-2y=-7 L3\implies 5x+4y=35
3 replies | 81 view(s)
• April 27th, 2017, 17:02
Let $g(x) = f(x) - 0.5x$. Can you use the given information (together with the intermediate value theorem and Rolle's theorem) to show that $g'(c) =... 9 replies | 168 view(s) • April 27th, 2017, 17:00 No, because for general f, f' is not necessarily continuous! (I said that in my original post). An example is f(x)= \frac{sin(x)}{x^2} if x is not... 9 replies | 168 view(s) • April 27th, 2017, 14:35 Since f''(x)\ge -1, f'(x)\ge -x+ C. Since f'(1)= 3, we know that C can be as large as 4. If f'(x)\ge -x+ 4 it will be positive for x less than 4. 1 replies | 64 view(s) • April 27th, 2017, 13:03 There are two things you need, both of which depend on the "mean value theorem". First, directly from the mean value theorem, since the slope of the... 9 replies | 168 view(s) • April 27th, 2017, 08:24 Since you only need to kill three of the four dragons, the obvious strategy is to not fight the dragon where you only have a 0.4 chance of winning. ... 2 replies | 64 view(s) • April 26th, 2017, 18:36 Your title, "Show this matrix is isomorphic to complex number" puzzled me! Individual matrices are not "isomorphic" to anything. What you mean is... 2 replies | 72 view(s) • April 26th, 2017, 14:47 I think you mean 30 cars per hour, not 30 miles per hour. The speed at which the cars pass does not seem to be relevant. If it's 30 cars per hour,... 2 replies | 71 view(s) • April 26th, 2017, 12:41 You can toggle editor modes with the top left button on the toolbar: If the background of the button is blue, then you are using the "Source... 3 replies | 73 view(s) • April 25th, 2017, 21:30 Attaching an image inline has nothing to do with using$\LaTeX$. To attach an image inline, follow these steps: 1.) Click the "Insert Image"... 3 replies | 73 view(s) • April 25th, 2017, 11:19 Here is this week's POTW: ----- Prove that there exist infinitely many integers$n$such that$n,n+1,n+2\$ are each the sum of the squares of...
0 replies | 43 view(s)
More Activity

### 4 Visitor Messages

1. Hey long time no see !
2. Glad to see you back here! You were missed.
3. Hi sbhatnagar! Did you read the PMs that I sent you? We are expecting a reply.
4. U are an IITian??

I am aspiring for it and writing it on Apr 8

Got any tips for me?
Showing Visitor Messages 1 to 4 of 4

Country Flag:
India

#### Statistics

Total Posts
95
Posts Per Day
0.05
Thanks Given
218
127
##### Visitor Messages
Total Messages
4
Most Recent Message
July 26th, 2013 14:11
##### General Information
Last Activity
July 26th, 2013 02:29
Last Visit
June 14th, 2013 at 05:15
Last Post
June 1st, 2013 at 09:34
Join Date
January 27th, 2012
Referrals
2
Referred Members
DigitalComputer, The Lord

### 22 Friends

1. #### AckbachOffline

Philosophus Nātūrālis

2. #### AlexYoucisOffline

MHB Apprentice

3. #### Also sprach ZarathustraOffline

MHB Apprentice

MHB Master

5. #### Chris L T521Offline

MHB Journeyman

MHB Master

7. #### DrunkenOldFoolOffline

MHB Apprentice

8. #### Fernando RevillaOffline

MHB Journeyman

9. #### HallsofIvyOffline

MHB Journeyman

10. #### JamesonOffline

Администратор

Showing Friends 1 to 10 of 22
Page 1 of 3 123 Last