Thanks for the help! I used KVL and got the correct answer, much appreciated :smile:
Vs - (R1*I) - Vc - (R3*I)=0
I=1.29 mA
VR3=I * R3
VR3=1.29 mA * 2.2k Ohm, (VR3: voltage over R3)
Ux=VR3 + Vc
Ux=3.71 V
1) The question in the task is: "What is the voltage across capacitor Ux 1ms after the switch "S" is closed?"
The capacitor is initially uncharged. I'm having difficulty obtaining the correct answer and identifying my mistake.
2) I recalculated and now obtained the Thevenin voltage (Vth) as...
Hi! I tried by using the Thevenin. Later using Vth and Rth to calculate Vs(0.1ms).
After that I divided the voltage from E over R1 and R3.
The circuit and my attempt: