• Today, 18:16
Ok, no problem. Thank you very much for your help!! (Smile)
10 replies | 75 view(s)
• Today, 16:42
Do you mean at the initial example or the fractions of the table of the picture? (Wondering)
10 replies | 75 view(s)
• Today, 16:26
Ah ok! Do the numberators have a specific pattern? The denominators are of the form $6^k$. (Wondering)
10 replies | 75 view(s)
• Today, 16:13
So, that table is in general incorrect? Or just for this example? (Wondering)
10 replies | 75 view(s)
• Today, 15:54
I understand that pattern! (Nerd) But I saw now the following table: Can this table be correct? In this table we don't have that...
10 replies | 75 view(s)
• Today, 14:14
Hey!! :o We consider the following game: We can roll a dice until a number appears twice. We can then write down as many points as the times...
10 replies | 75 view(s)
• February 1st, 2018, 14:42
So we get the linear spline function: \begin{equation*}s(x)=\begin{cases}p_1(x)=x+1 & x\in \\ p_2(x)=2x+1 & x\in \end{cases}\end{equation*} If...
3 replies | 93 view(s)
• February 1st, 2018, 14:25
So, we get the following: \begin{equation*}|g'(c)|<2.4 \Rightarrow \frac{|g(y)-g(x)|}{|y-x|}<2.4 \Rightarrow |g(y)-g(x)|<2.4|y-x|\end{equation*} ...
17 replies | 195 view(s)
• February 1st, 2018, 14:12
Since $g''(x)>0$ for $x\in \Omega$. So, the derivative $g'$ is increasing. That means that $x\geq \frac{3}{5}\Rightarrow g'(x)\geq g'\left... 17 replies | 195 view(s) • February 1st, 2018, 13:40 We have that$g''(x)=\frac{5}{4}x^{-6}$which hasn't any roots. Does this mean that the minima or maxima, if they exist, must be on the boundaries?... 17 replies | 195 view(s) • February 1st, 2018, 13:16 Hey!! :o We want to construct a linear spline that at the points$x_0=-1$,$x_1=0$,$x_2=1$has the values$b_0=0$,$b_1=1$and$b_2=3$. The... 3 replies | 93 view(s) • February 1st, 2018, 12:44 We have that$g(x_0)=\frac{4x_0}{5}+\frac{x_0^{-4}}{16}=\frac{4\cdot 0.9}{5}+\frac{0.9^{-4}}{16}\approx 0.8>\frac{3}{5}$. So, we have for each... 17 replies | 195 view(s) • February 1st, 2018, 12:16 That means that$g(x)\geq g(x_0)$for every$x\in \Omega$, right? So we have to calculate the value of$g(x_0)$, right? (Wondering) ... 17 replies | 195 view(s) • February 1st, 2018, 11:52 mathmari replied to a thread [SOLVED] Gauss Quadrature in Advanced Applied Mathematics Ah I see!! Ah ok! 2 replies | 113 view(s) • February 1st, 2018, 11:35 How do we know that? (Wondering) From the Mean Vaue Theorem we have that for$x,y\in \Omega$and$c\in $: ... 17 replies | 195 view(s) • February 1st, 2018, 11:27 But it is a local minimum, can we say that for every$x\geq \frac{3}{5}$it holds that$g(x)\geq g(x_0)? (Wondering) 17 replies | 195 view(s) • January 31st, 2018, 13:19 \begin{align*}&g(x)=x-\frac{x^5-\frac{5}{16}}{5\cdot x^4}=x-\frac{x^5}{5\cdot x^4}+\frac{\frac{5}{16}}{5\cdot... 17 replies | 195 view(s) • January 31st, 2018, 12:19 Hey!! :o I am looking at the Gauss Quadrature to approximate integrals. I haven;t really understood the meaning of the weighting function. Could... 2 replies | 113 view(s) • January 31st, 2018, 09:05 Hey!! :o We have the functionf(x)=x^5-\frac{5}{16}$. I have approximated the root of that function using three steps of Newton's method with... 17 replies | 195 view(s) • January 29th, 2018, 09:36 Ok! Thank you!!! (Yes) 2 replies | 89 view(s) • January 29th, 2018, 05:01 Hey!! :i How many homomorphism$f:\mathbb{Z}_4\rightarrow S_4$are there? Do we have to find how many permutations of$S_4$have order that... 2 replies | 89 view(s) • January 28th, 2018, 10:54 Let's consider a specific example. An employee starts work around 8:00 am The general beginning of duty varies by up to$2\$ minutes up or down....
3 replies | 113 view(s)
• January 28th, 2018, 09:51
Hey!! :o I am looking at the Likelihood function. I have understood how we define that function, but having find the maximum of the Likelihood...
3 replies | 113 view(s)
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