Recent content by RuthlessTB

Homework Statement A hoop with mass m= 10 kg, radius r=0.6 m, and moment of inertia I=mr^2 is rolling without slipping with a linear velocity of 8.5 m/s. What is the total kinetic energy (in J). Homework Equations K=1/2 m v^2 Kr=1/2 I ω^2 The Attempt at a Solution The kinetic...

In elastic collision, momentum before equals to momentum after (Pi=Pf). (M1*V1) + (M2*V2) = (M1 * V1') (M2*V2') 1) 12= (4 * V1') + (2 * V2') V1 - V2 = -(V1' - V2') 2) 3-0 = -(V1' + V2') 3 + V1' = V2' By substitution to get V1' 12 = (4*V1') + (2 * (3+V1')) Therefore, V1'= 1 m/s...

Homework Statement A block with mass 4 kg and velocity of 3 m/s collides elastically with block B with mass 2 kg which is originally at rest. Find the velocities of the two blocks after the collision.Homework Equations P= m * vThe Attempt at a Solution This is the first time I try to solve an...

I got it now, I really appreciate your help.. thanks :)

Well the final answer will be 400 J Can I know why this is the proper way? Is it a special case for projectiles or something? or the way I used is wrong in general?

Oh now I got it.. First Ki= 0.5 m vi^2 Kf= 0.5 m vf^2 Ui= m g h Uf= 0 ****************** ΔK + ΔF = 0 which will end up (v^2 - vo^2) + (-mgh) = 0 (v^2 - 400) + (-200) = 0 v^2= 200+400 = 600 m/s Kf= 0.5 m v^2 Kf= 0.5 (1) (600) = 300 J ****************** Is my solution right?

Homework Statement A 1kg mass is projected from the edge of a 20m tall building with a velocity of 20 m/s at some unknown angle above the horizontal. What is the kinetic energy (in J) of the mass just before it strikes the floor? Homework Equations K= 1/2 m v^{2} The Attempt at a...

m1: T - 0 = m1 a m2: m2g - T = m2 a I need now to calculate acceleration first in order to get the value of the tension T = m1 a -T + m2g = m2 a [m2g = a(m1+m2)] 50 = a(12+5) a= 50/17 = 2.94 m/s^2 Now to calculate the tension T= m1 a T= 12 (2.94) = 35.3 N My question is...

Homework Statement Homework Equations ƩF=0 ƩF= m a The Attempt at a Solution Since there is no friction do I assume the objects will move? or it will remain equilibrium since m1 is 120N which is way higher than 50N.

Thank you, I used the second equation and the answer is 2.4 s.. is it right?

Homework Statement A ball is kicked with initial velocity 40 m/s at an angle of 37 degree above the horizontal. What is the time (in seconds) needed to reach the maximum height? Homework Equations Y-axis h= Voy t - 0.5 g t^2 Vy= Voy - g t Vy^2= Voy^2 - 2 g h X-axis d= Vox t Vx=...

Homework Statement Q: A stone is thrown vertically upwards with initial speed of 5 m/s from edge of a cliff 30 m high. Find the time needed for the stone to reach the ground (in seconds). Homework Equations 1. (h= Vo t - 0.5 g t^2) 2. Quadratic equation: The Attempt at a Solution...

I got it right now, but please check my steps if there is a mistake or not. X=0.5 (V+Vo) t 800=0.5 (20+Vo) 25 800=12.5 (20+Vo) Now since 12.5 (20+Vo) = 800 20 + Vo = 800/12.5 20 + Vo = 64 Vo = 64-20 = 44 m/s Acceleration: V= Vo + a (25) 20= 44 + a (25) 20-44= a (25) -24= a (25) a 25 = -24 a =...

X=0.5 (V+Vo) t 800= 0.5 (20+Vo) 25 800= 12.5 (20+Vo) 800= 250+Vo Vo+250=800 Vo=800/250= 3.2 m/s. Is that right? If so, can you help me to find out the acceleration? I tried using this equation V=Vo+a t But it gives me a different answer which is wrong. Here what I did V=Vo+a t^2 20=3.2+ a...

Actually my instructor is horrible, he just gives the laws or equations with some simple information and moving on. I am self-studying this that is why I am facing difficulties. Anyway, got to try to solve it later and post my solution.