Hi Diflection,
Indeed that's a good thing to remember. However, in the few months that passed by since I posted it, I already passed the course :).
Thanks for your help,
Robin
Is there anyone who can enlighten me?
Latex does work now, I'll restate the relevant equations (I can't edit my post)..
2. Homework Equations
a)
\theta=\frac{TL}{GJ}
For closed:
J=\frac{\pi}{2(R_0^4-R_0^4)}
Ro=Outer radius
Ri=inner radius
For open:
J=\frac{st^3}{3} =>...
I guess the beam then bends with
\delta_{max}=\frac{Pl^3}{48EI}
Is that correct? But how can I calculate the I, what is the neutral axis? Is that just the horizontal line through the centroid (because I use the deflection with a force in the shear center)..? And how do I use the Poisson...
I've thought a bit more about it, but I'd like to know if I'm thinking in the right direction.. I think the person should stand on the spot of the picture, exactly in the middle (seen longtitudinal perspective) of the beam for maximum deflection. Then the beam will rotate and bend. Am I supposed...
Homework Statement
a) Determine what the thickness should be in a closed tube versus an open tube to have the same twist angle
b) Determine what the thickness should be in a closed tube versus an open tube to have the same max shear stress
G=20GPa
T=50Nm
tr=1mm (for the open tube)...
Homework Statement
The problem is to determine the maximum deflection when a person is standing on the beam in the attachment.
E= 206.8 GPa, v=0.3
Homework Equations
(although I am not completely sure if this one is relevant)The Attempt at a Solution
I've thought a bit about the problem...