Recent content by requied

How can I' be the formula above? Is there any formula to get this same

I was studying on partial derivatives, chain rule etc uptill now. Deadline of the homework is tomorrow night. I guess I will not be able to complete the homework. If someone would give me the solution I really appreciate it. Else I will quit the question. I know that here is not a question...

This is a piece of a spectrometer question and this region above is the velocity selector region. The question says "What should be the power of the voltage supply that we will use in velocity selector region?". I think it is not a problem to just take this area about the question. I assumed...

I didn't ask the question for anything about the kinetic energy of the particle. You misunderstood me . I just wondered that what is the voltage supply's power.

It's that easy really? I supposed that I would do some complex calculations :/

I spesified it on the homework statement.

I know only these relevant equations for power. But here there is a different situation, we have a parallel plates which we don't have to know I current. How should I think of about this? I wonder if it can be thought of a capasitor or something? Assume that also we know E, B and velocity .

And also, how can I calculate power of this voltage supply? This can be thought of a capacitor?

In velocity selector region, the question says "determine" but I did it like this below. I chose the voltage necessarily. Is there another way to determine these values?

Thanks for everything ! All the best

Would you like to add something else? Because I am starting over to do the homework.

I'll be hanged if I understand! Pardon but I'm just not be able to do these calculations. I'll glance at chain rule of partial derivatives. I guess we couldn't make progress.

I did what you said at #9. Can you check out that for me?

I was talking about the same thing at #31. And because of we can't use these as m2-m1 in ## (r_2 - r_1) = r_2 (1 - \sqrt{\frac{m_1}{m_2}})## I calculated these m2 and m1 one by one. So in this way, we don't have to use actual mneutron I think. What do you think?

I found the potential function u like this: I don't know why but it seems correct to me.