It's 12:11 here and this is time for bed this is clearly the reason for this unforgivable mistake :).
well, I can't think of anything but (f*pi''maximum angle''/2*pi ''the total period'') *L.
well, simply measure the initial {\theta} and then {\theta} at some stop time ##t##, then multiply the result with ##L##.
why does having ##t## as a parameter doesn't make sense?
Oh, yeah I just realized that I inadvertently wrote down the cos function where it should be the sin function instead, is it right now?
And what do think about this expression for Vo?
1.
but it doesn't add anything because the solution theta= A cos(theta) 'let's ignore the sin term' at t =0 is
theta = A and from the problem, this is just zero.
Right?
Summary: Hi, I'm trying to solve this problem, if it's not right then please help me with a hint without solving it.
This formula is just an approximation for small values of theta, but if Vo was greater than the denominator this will lead to large values of theta and then this solution is not...
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