Recent content by PolyFX

  1. P

    How do I use Fermat's Little Theorem to solve for x in F19?

    Hi, I'm a little lost as to how to use Fermats Little Theorem to simplify. 2-100 mod 19 Since 19 is prime then that should mean that 218 mod 19 = 1. So, 2-100 mod 19: = 218 * -5 + (-10) mod 19 =(218)-5 * 510 mod 19 = 1-5 * 510 mod 19 = 510 mod 19 I need some assistance after this part...
  2. P

    How do I use Fermat's Little Theorem to solve for x in F19?

    Haha of course. Yep, I plugged in 40 back into the original equation and I got 3x + 50 = 11 mod 53 3(40) + 50 = 11 mod 53 120 => 11 mod 53 However, I have another question Say you're given something like this "Solve 7x + 2 = 2-100 in F19" I tried doing this the same way as...
  3. P

    How do I use Fermat's Little Theorem to solve for x in F19?

    Hi micromass, So 3x = 14 mod 53 18 * 3x = 18 * 14 mod 53 Is it safe to assume that 18 * 3x = x since 3*3-1 = 1? therefore x = 18 * 14 mod 53 = 252 mod 53 = 40 mod 53 Is this the correct approach? -Thanks
  4. P

    How do I use Fermat's Little Theorem to solve for x in F19?

    Homework Statement Solve 3x + 50 = 11 in F53 Homework Equations Extended Euclidean AlgorithmThe Attempt at a Solution To find 3-1 mod 53 using the euclidean algorithm: gcd(53,3) 1)53/3 = 17 + 2R 53 = 17 * 3 + 2 2 = 53 - 17 * 3 3/2 = 1 + 1R 3 = 1 * 2 + 1 1 = 3 - 1 * 2 = 3 - 2Now...
  5. P

    Diophantine Equation(Example Run-Through)

    Hi icystrike, I'm not sure what you mean. After getting all the equations you just continue to use back substitution, right? I'm having trouble simplifying the expression after using back substitution. For example in the text gcd(330,156): 330 = 156 * 2 + 18 which implies 18 = 330...
  6. P

    Diophantine Equation(Example Run-Through)

    Extended Euclidean Algorithm(Example Run-Through) Homework Statement I need help tracing through an example of Diophantine Equations. The question: Find integers x and y such that 37x + 29y = 1. Homework Equations The use of Euclidean Algorithm is required. The Attempt at a...
  7. P

    Combinational Logic-Decoders(basic)

    Homework Statement I have a basic question regarding the truth table for decoders and encoders. Let's say for a 3 to 8 line decoder with inputs x y z and outputs F0...F7 The truth table is x y z | F0 F1 F2 F3 F4 F5 F6 F7 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 1 0...
  8. P

    What Is the Probability of Choosing a Hexadecimal Number with Distinct Digits?

    1. Homework Statement 1.(a) How many 4 digit hexadecimal numbers can be formed using the hexadecimal digits 1. 5, 6, 9, A, C?(Repetition is allowed) (b) How many four digit hexadecimal numbers with distinct digits can be formed using the hexadecimal digits above? (c) What is the...
  9. P

    Help Calculating Pi using Arctangent formula

    Homework Statement Using the Arctangent formula pi = 16 * arctan (1 / 5) - 4*arctan(1 / 239) to calculate the value of pi to 53 significant digits.Homework Equations The power series of arctangent(x) is = x − x^3/3 + x^5/5 − x^7/7 + x^9/9... The Attempt at a Solution...
  10. P

    How do I change the variable in this expression?

    Hi sorry for the late reply, I am still somewhat confused about how to approach this question. So far this is how I've startend it. Let j = K+1/K+2 Therefore when k = 0, j = 1/2 and when K = n - 1, j = (n-1) + 1 / (n-1 ) + 2 j = n So I introduce another variable for the other...
  11. P

    How do I change the variable in this expression?

    Homework Statement Rewrite the following expression as a single product. Hint: Perform a change of variable first. Homework Equations The Attempt at a Solution I looked at the example from the book regarding a change of variable. They first started out by calculating the upper and lower...
  12. P

    Equivalence Classes Homework: (a) & (b)

    Oh I see now. so 5 mod 2 = 1 c mod 2 = 1 therefore c can be 5, 7, 9, 11, etc. since 7/2 has a remainder of 1 and 9/2 has a remainder of one. Similarly, 3 mod 3 = 0 so; d mod 3 = 0 therefore d can be 3, 6, 9, 12 etc. So would 4 ordered pairs be; (5,3), (7,6), (9,9)...
  13. P

    Equivalence Classes Homework: (a) & (b)

    Hi mark thank you for your reply, So "a mod b" is always going to produce an integer "b - 1"? So for part a here is what I have so far; a == c mod 2 => a mod 2 = c mod 2 we let a = 5 so 5 mod 2 = c mod 2 Is this correct so far? -Thank you in advance.
  14. P

    Equivalence Classes Homework: (a) & (b)

    Homework Statement \forall (a,b), (c,d) \in (Z^2), (a,b)D(c,d) \leftrightarrow a\equiv c\mod\2\and\b\equiv d mod 3 *edit* Sorry the b = d mod 3 is all part of the same line. (a) List four elements of the equivalence class [{5,3}] (b) How many equivalence classes of D are there in total...
  15. P

    Evaluating Indifinite Integral

    hi, sorry for the late reply. Solving for dx I got dx= du/(Sec^2(3x)) x 3 So Sec^2(3x)e^u du/sec^2(3x) x 3 sec^2(3x) cancel each other out? so I'm left with e^u(du)(1/3) = 1/3e^u(du) so 1/3e^(tan(3x))+C? Is my approach correct? -Thank You
Back
Top