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phantomvommand's latest activity
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phantomvommand
replied to the thread
Range of an object launched on a downward hill
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I do not agree with your claim that range is maximised when launched at 45 degrees to the hill. The result of the problem suggests that...
Today, 11:34 AM
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phantomvommand
replied to the thread
Range of an object launched on a downward hill
.
I certainly think that there is some confusion here. I believe that the outline of the proof of the author is as such: 1. Consider the...
Today, 7:40 AM
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phantomvommand
replied to the thread
Range of an object launched on a downward hill
.
The question does ask for the angle of launch so as to maximise range, so it is definitely relevant. But why is it that for the...
Today, 5:50 AM
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phantomvommand
posted the thread
Range of an object launched on a downward hill
in
Introductory Physics Homework Help
.
I managed to solve this by tilting the axes along the hill, and calculating the range, and then differentiating wrt ##\theta## (angle...
Yesterday, 3:08 PM
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phantomvommand
reacted to
BvU's post
in the thread
X and Y coordinates of an oscillating object on a spring.
with
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So: no! Spring not stretched in the ##y## direction at ##t=0## doesn't mean never stretched. ##\dot y \ne 0## at t=0 means it does gets...
Thursday, 8:19 PM
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phantomvommand
reacted to
BvU's post
in the thread
X and Y coordinates of an oscillating object on a spring.
with
Like
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In first instance this is math. You have two seond order differential equations, so four initial conditions. For example ##x, \dot x, y...
Thursday, 8:19 PM
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phantomvommand
reacted to
haruspex's post
in the thread
X and Y coordinates of an oscillating object on a spring.
with
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except that, as indicated later, the amplitude and phase constants can be different. Only the frequency must be the same. Easily...
Thursday, 8:19 PM
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phantomvommand
posted the thread
X and Y coordinates of an oscillating object on a spring.
in
Introductory Physics Homework Help
.
I get that: ##x(t) = A\cos(\omega t + \phi)## ##y(t) = A\sin(\omega t + \phi)## (from the above relevant equations). This agrees with...
Thursday, 3:39 AM
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phantomvommand
reacted to
TSny's post
in the thread
Kinematics: Acceleration of a figure skater changing direction
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This is interesting. Consider the case where the velocity changes 90 degrees, starting East and ending North. The diagram shows the...
Thursday, 3:27 AM
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phantomvommand
reacted to
haruspex's post
in the thread
Kinematics: Acceleration of a figure skater changing direction
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Friction opposes the relative motion of surfaces in contact. If you are facing North and attempting to run straight ahead but you are...
Monday, 4:40 AM
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phantomvommand
reacted to
Orodruin's post
in the thread
Kinematics: Acceleration of a figure skater changing direction
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To change a velocity between any two given velocity values if acceleration is limited to a particular magnitude is the straight line in...
Monday, 4:40 AM
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phantomvommand
replied to the thread
Kinematics: Acceleration of a figure skater changing direction
.
How did you know that acceleration's direction is constant in the above question? And in that case, would it be correct to say that...
May 12, 2024
P
phantomvommand
posted the thread
Kinematics: Acceleration of a figure skater changing direction
in
Introductory Physics Homework Help
.
My guess was simply that as acceleration changes from the north to east direction, the total magnitude change of v is ##v \sqrt 2##...
May 12, 2024
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