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• Today, 03:42
Hi Hugo ... Thanks again for your help ... Hope that despite the heat, you enjoy your holiday ... It gets hot down here sometimes ... even...
7 replies | 109 view(s)
• Today, 03:31
Trying Steenis' idea ... Practice values for first statement in the proof of Theorem 12.9 in Browder ... ... that is practice values for n...
3 replies | 91 view(s)
• Today, 03:12
I understand your hesitation. Right now, I am on holidays in Saigon, Vietnam. I have time to follow MHB, but I have trouble focusing. What do you...
7 replies | 109 view(s)
• Today, 02:23
Thanks for such a clear and honest post, Hugo ... Still reflecting on your new answer to the issue ... Does anyone else have an answer ...?
7 replies | 109 view(s)
• Today, 02:05
Q1: that is correct Q2: I understand what you mean regarding the parenthess and I tried to give an answer in that direction. But I was not happy...
7 replies | 109 view(s)
• Today, 00:24
Hi joypav, The result your advisor mentioned is the Riesz representation theorem. There are many books, websites, and papers that you can look to...
1 replies | 35 view(s)
• Yesterday, 23:43
Thanks Steenis ... your post really got me thinking ... Yes ... important point that ... ... " ... By definition 12.8, you can only multiply two...
7 replies | 109 view(s)
• Yesterday, 22:22
Here's a link to a Desmos slope field for this ODE: https://www.desmos.com/calculator/my0rwuxl5x
3 replies | 71 view(s)
• Yesterday, 18:46
topsquark replied to a thread Jokes in Chat Room
It's a rectangular number because you write it out by making a rectangle on the number pad... -Dan
216 replies | 33267 view(s)
• Yesterday, 18:39
Olinguito replied to a thread Jokes in Chat Room
Such a number is a cyclic permutation of $\overline{abcd}$ where $$a\ =\ a \\ b\ =\ a+k \\ c=a+k+l \\ d=a+l$$ where $a$ is the bottom-left digit...
216 replies | 33267 view(s)
• Yesterday, 01:37
By definition 12.8, you can only multiply two tensors. If you want to multiply 3 tensors, $\alpha \otimes \beta \otimes \gamma$, the trick is to...
7 replies | 109 view(s)
• Yesterday, 00:37
When you determine your integrating factor, you need only determine up to but not including the constant of integration: ...
3 replies | 71 view(s)
• February 20th, 2019, 07:21
Looks great to me. Nicely done!
7 replies | 109 view(s)
• February 20th, 2019, 06:55
Here's something to start you off. The axis of symmetry for the parabola y = ax^2 + bx + c is x = -\dfrac{b}{2a} and if an x-intercept is at (-2, 0)...
2 replies | 67 view(s)
• February 20th, 2019, 03:31
Hi Tan Tom, welcome to MHB! ;) If I understand correctly, you have $$(1-2j)e^{j\frac\pi 2 n} +a_3 e ^ {-(j\frac\pi 2n)} + 3 + (-1)^{n+1}=sum$$...
1 replies | 58 view(s)
• February 20th, 2019, 00:25
THanks Steenis ... Good idea ... Peter
3 replies | 91 view(s)
• February 20th, 2019, 00:16
Maybe it is an idea to practice first with $$n=1, r=1$$ then $$n=2, r=1$$ $$n=2, r=2$$ $$n=3, r=1$$ $$n=3, r=2$$ $$n=7, r=3$$ and so on
3 replies | 91 view(s)
• February 19th, 2019, 21:44
I am reading Andrew Browder's book: "Mathematical Analysis: An Introduction" ... ... I am currently reading Chapter 12: Multilinear Algebra ......
7 replies | 109 view(s)
• February 19th, 2019, 20:32
There are some typos/issues with your work. See if you can spot them...:)
4 replies | 84 view(s)
• February 19th, 2019, 20:03
Yep. (Nod)
9 replies | 150 view(s)
• February 19th, 2019, 18:40
Correct. (Nod)
9 replies | 150 view(s)
• February 19th, 2019, 17:48
We have the property that the product of an invertible matrix with another matrix has the same rank as that other matrix. Can we prove that...
9 replies | 150 view(s)
• February 19th, 2019, 15:45
Congratulations! :cool:
4 replies | 85 view(s)
• February 19th, 2019, 15:41
Okay, if we are to consider a solution of the form: y=t^r Then: y'=rt^{r-1} y''=r(r-1)t^{r-2}
4 replies | 84 view(s)
• February 19th, 2019, 11:04
Congratulations on a well-deserved promotion, steenis!
4 replies | 85 view(s)
• February 19th, 2019, 11:00
Here is this week's POTW: ----- If $x^2-x-1$ divides $ax^{17}+bx^{16}+1$ for integer $a$ and $b$, find the possible value of $a-b$. ----- ...
0 replies | 66 view(s)
• February 19th, 2019, 10:58
Congratulations to castor28 for his correct solution(Cool), which you can find below: There is an obvious solution $x=y=0$; furthermore, as the...
1 replies | 166 view(s)
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#### February 19th, 2019

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