Recent content by Ofinns

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    Time derivative of gravity due to acceleration

    Homework Statement We have the equation for gravity due to the acceleration a = -GM/r2, calculate velocity and position dependent on time and show that v/x = √2GM/r03⋅(r/r0-1) Homework Equations x(t = 0) = x0 and v(t = 0) = 0 The Attempt at a Solution v = -GM∫1/r2 dt v = dr/dt v2 = -GM∫1/r2...
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    Calculate momentum, kinetic energy, speed etc. for a decay

    Thank you for all your help. Well.. a massless particle should have the speed of light of course. - . - You don't have any idea how to calculate the mass for K+ ?
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    Calculate momentum, kinetic energy, speed etc. for a decay

    Well everything if I'm going to be honest. But okey.. 1. Relativistic formulas: E2 = p2c2 + m2c4 E2 - p2 = m2 The difinition of of kinetic energy is the total energy E minus the rest energy, giving us this: Ek = √(p2c2+m2c4) - mc2 Where the mass and kinetic energy are for the μ+. But can I...
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    Calculate momentum, kinetic energy, speed etc. for a decay

    Um, could you by any chance elaborate a bit on this?
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    Calculate momentum, kinetic energy, speed etc. for a decay

    Homework Statement I have the decay K+ → μ+ + νμ Calculate: 1. Momentum of μ+ 2. Total energy of νμ 3. Mass of K+ 4. Speed of μ+ 5. Speed of νμ Homework Equations The only thing we get are the kinetic energy of μ+ so Kμ+ = 152.53 MeV and the mass of mμ+ = 105.658 MeV/c2 The Attempt at a...
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    I Harmonic Oscillator in 3D, different values on x, y and z

    Right, of course. Thank you.
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    I Harmonic Oscillator in 3D, different values on x, y and z

    Late questions.. but why is w2=2w and not 4w?
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    I Harmonic Oscillator in 3D, different values on x, y and z

    Oh! Thank you so much for the answers, this has been bugging me for a while now. Best regards
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    I Harmonic Oscillator in 3D, different values on x, y and z

    Why is it 2? What formula do you use to calculate that? (Sorry for all the questions..)
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    I Harmonic Oscillator in 3D, different values on x, y and z

    Thank you, now I understand that part. What will the degeneracy become for the 1st excited state then? Can I use the same formula gn = 1/2(n+1)(n+2) for this case?
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    I Harmonic Oscillator in 3D, different values on x, y and z

    Can you elaborate on that? Is 4y2 just n2 here? And in that case you will get three different energy values: E100 = 3hw1/2 E010 =6hw2 E001 =3hw3/2 Which one is the 1st excited state? Is it E010?
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    I Harmonic Oscillator in 3D, different values on x, y and z

    Hi, For a harmonic oscillator in 3D the energy level becomes En = hw(n+3/2) (Note: h = h_bar and n = nx+ny+nz) If I then want the 1st excited state it could be (1,0,0), (0,1,0) and (0,0,1) for x, y and z. But what happens if for example y has a different value from the beginning? Like this...
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