Okey, that's a relief I started going crazy.
Since I'm not familiar with those notations I'm trying to get everything step by step and all was clear till this point.
I'll take a more relaxed approach :)
Thanks !
So if in that particular case (9) follows (8), by changing indices it's equivalent to \begin{equation}\frac {\partial x^{k}} {\partial x'^{h}} = R^{kh} ,\end{equation} so I don't see what's wrong :cry:
Besides I understand that \begin{equation}\frac{\partial x’^i}{\partial x^j} \neq...
Thanks for the tips, and so sorry about the poor notation. I'll try to be more explicit.
In his paragraph he demonstrates that the derivative of a vector field
\begin{equation}
V'^{i}(\vec x') = R^{ij}V^{j}(\vec x)
\end{equation}
transforms like
\begin{equation}
\frac {\partial V'^{i}(\vec x')}...
Hi there,
I'm just starting Zee's Einstein Gravity in a Nutshell, and I'm stuck on a seemingly very easy assumption that I can't figure out. On the Tensor Field section (p.53) he develops for vectors x' and x, and tensor R (with all indices being upper indices) : x'=Rx => x=RT x' (because R-1=RT...