Recent content by niko_niko

That is exactly the crux of my issue. I was able to obtain the same equations in my solution but I was utterly confused why the author seemingly did a switcheroo.

To everything you have stated, I agree. However, my objection does not come from the portion of the solution you have pointed out. Rather, here: I believe the continued solution here contradicts with the established accelerations in the previous portion of the solution.

I shall refer to ##m_2## as the top block for convenience. As for the horizontal acceleration of the top block relative to the ground frame, it should be ##a-A##. However, as I have said, the solution says it is simply ##a##. As for ##m_1## which I shall refer to as the hanging block, the...

I am convinced that the solution to this problem has to be a mistake for the reason that the accelerations of the top block ##m_2## and the hanging block ##m_1## are simply inconsistent with each other. To reiterate, the solution in item (b) says that the acceleration of the top block is ##a##...

That would be what I would imagine for the case of F=0, yes. Which means the acceleration of the top block should be a-a_B, right?

Hmm. Does the large block accelerate in the positive x direction? My assumption is that it should move to the left due to the force exerted by the rope.

It seems my question got duplicated. Could the moderators close the other thread: https://www.physicsforums.com/threads/confusion-on-accelerations-of-system-of-cart-blocks-and-pulley.1053967/

Yes. Those are the exact equations that were provided. For reference, I attached the solution my professor gave me containing those equations.

But in the solution provided for (b), my professor used a instead of a-A. Likewise, in (d) the acceleration for the hanging mass was a-A according to the solution.

So in that case, the solution provided for (b) should be the acceleration for the hanging mass and not the top mass. Am I correct?

Well, looking at the second law equations he wrote, I would assume a is measured relative to the ground given that it took into account the acceleration A of the cart. But when he solved for the acceleration of ##m_2## for item (b) he seemed to only use a, as shown in the image below.

Yes, that is also what my professor showed me.

Forgot to attach sorry. Here it is.

I'm having trouble understanding the solution my professor gave me, in particular, the accelerations of ##m_2## and ##m_1##. When my professor solved for the acceleration of ##m_2##, he used ##a## as the acceleration but when I look at the second law equation for ##m_2## as shown in eqn. [1]...

[Mentor Note -- Two threads on the same by the OP have been merged into one] I'm having trouble understanding the solution my professor gave me, in particular, the accelerations of m_2 and m_1. When my professor solved for the acceleration of m_2, he used a as the acceleration but when I look...