Recent content by nikk33213

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    Related rates problem for the dimensions of a cylinder

    given: dr/dt=3, v=1115, h = 44, dh/dt = ? v= (pi)r^2(h) dv/dt = 2(pi)r(dr/dt)(h) + (pi)r^2(dh/dt) 0 = 2(pi)r(3)(44) + (pi)r^2(dh/dt) 1115 = (pi)r^2(44) r = 2.84012 0 = 2(pi)*3*2.84012*44 + (pi)(8.066262)(dh/dt) (-2355.540034)/(25.340909) = dh/dt -92.954 = dh/dt Is this correct?
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    Related rates problem for the dimensions of a cylinder

    TL;DR Summary: related rates problem The radius of a cylinder is increasing at a constant rate of 3 meters per minute. The volume remains a constant 1115 cubic meters. At the instant when the height of the cylinder is 44 meters, what is the rate of change of the height?
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