Ok, so I can see the square wave and it's periodicity. Am I right in thinking that, since what we are trying to find is U(y,t) from 0 to 2L, function from -2L to 0 is set up in this fashion just for the convenience of working out the Fourier coefficients?
I get An=(2q1/npi)cos(npi).
Surly if you change the variable then the initial condition is not just U = -q1 at t = 0 for all y, instead U = 0 at y = 0 and y = 2L, and then U = -q1 elsewhere. This is from the initial condition that the flux is q1 at x= ± L. Does this not make the calculation of the Fourier coefficients very...
Thanks very much Chet! That was a great help. I have now solved the differential equation, or at least I think I have. I was wondering if you would check my working. I apologize in advance for not using latex but I don't know how.
Firstly I defined a new function:
U(x,t) = q(x,t) -...
Hi Chet.
I'm not quite sure what you mean by "write down the transient heat conduction". I'm fairly sure the system would reach equilibrium where difference in temperature between the two ends provides a flux through the solid which is the same as that which occurs at x = L. I suppose that...
1D solid, 0<x<L, with the following boundary conditions:
The whole solid is at T = T1 at t=0. x = 0 is held constant at initial temperature T1 for all t. There is a constant flow of heat, dQ/dt out of the solid at x = L.
T(0,t) = T1,
T(L,0) = T1,
How do we go about solving the heat equation...