Recent content by New-Blu-Blood

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    How High Was the Girl Above the Water When She Released the Rope?

    Ok, I think I messed the calculation up a little. Here should be the correct calculation. y= (2.10 x sin 35).615 - .5(-9.80).6152 = 2.59 or 3
  2. N

    How High Was the Girl Above the Water When She Released the Rope?

    Homework Statement On a hot summer day, a young girl swings on a rope above the local swimming hole . When she let's go of the rope her initial velocity is 2.10 m/s at an angle of 35.0 degrees above the horizontal. If she is in flight for 0.615 s, how high above the water was she when she let...
  3. N

    Vector Problem: Avg Acc Components

    Homework Statement Initially, a particle is moving at 4.40 m/s at an angle of 35.0 degrees above the horizontal. Two seconds later, its velocity is 6.35 m/s at an angle of 58.0 degrees below the horizontal. What was the particle's average acceleration during these 2.00 seconds in terms of the...
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