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okay, let me know what you think about my work please, my final result is: (-R^2 * i0)/(4h^2 (h^2 + R^2))
with: R: radius of detector, h: distance between the detector and the source, i0: intensity at the source.
thanks
hahahaha sure, i will try to explain the best i can:
first i used Pythagoras to find the distance (sqrt(r^2+h^2))
then i used the inverse square law to find the intensity when the radius is r (ir=i0/(4.pi.d^4))
then i integrated ir*Ar (area) from 0 to R (max radius)
Ar changes depending on the...
i need to account for for the change in distance, but even if i find a way to calculate it, i can't figure out how to find the air to apply the intensity over(i thought about doing an integral with the circumference, what do you think?)
what do you mean?
does your solution account for attenuation, and the angle at which it hits the detector(the bigger the angle the fewer particles hits the detector)?
thanks
nadi