If the cosine is negative, then the angle is between 90 and 270 degrees. So the angle is 213.7 or 146.7 degrees? Was I completely off track originally then? I still feel like my original approach makes sense... except for the fact that your point makes my original answer definitively wrong. Thanks!
Homework Statement
Vectors A and B have scalar product -6.00 and their vector product has magnitude 4.00. What is the angle between these two vectors?Homework Equations
A \dot B = ||A|| ||B|| cos θ and
A \cross B = ||A|| ||B|| sin θThe Attempt at a Solution
Then I reasoned that tan(θ) = -4/6 so...