Recent content by Mikesgto

  1. M

    General Engineering Dimensional Analysis

    Well T=1/s which is included in my original Pi group of g/(T^2*L). But once I have one pi group, which is all I can have because I have 4 variables and only 3 basic dimensions, how do I go about relating that to solving for the variables? Correct me if I'm wrong, but mass should not play a...
  2. M

    General Engineering Dimensional Analysis

    Ok so perhaps my attempt wasn't completely written above. I wrote down all the units, namely meters, m/s^2 for gravity and kg for mass. That's the only pi group I can think of but then I can't figure out the steps to solve for 3 individual exponents.
  3. M

    General Engineering Dimensional Analysis

    The period T of a pendulum of length L, mass m in a gravitational field g ms-2 is suspected to be a function of L, m and g. If it is postulated that T=KLxmygz where K is a dimensionless constant, use dimensional analysis to obtain the constants x, y and z. There's only one pi group I came up...
  4. M

    First order linear differential equation

    Homework Statement 11(t+1)dy/dt-7y=28t y(0)=13 Homework Equations The Attempt at a Solution I got µ(x)=1/(t+1)^(7/11) and then used 28/11(t+1)^(7/11)*integral of t/(t+1)^(18/11) dt. And that's where I'm stuck.
  5. M

    Laplace Transformations Step Functions

    Thanks so much for all the help. The next part of my solutions are finding out F(s). Do I treat the -3t attached to the U9(t) as my f(t)?
  6. M

    Laplace Transformations Step Functions

    ok, so the next problem i have is attached and the solution i came up with is 3t-3tU9(t) Am I on the right path there?
  7. M

    Laplace Transformations Step Functions

    5t-5U6(t)(t-6) I got this one after a ton of work, but I am failing to grasp the concept going behind this.
  8. M

    Laplace Transformations Step Functions

    Homework Statement The attachment is the problem. Homework Equations The Attempt at a Solution I understand how to go about solving the laplace transformations but I have no idea how to start with the Heaviside functions for the 5t and the 30. What I got was 5t+30U6(t) but it turned...
  9. M

    Second Order Linear Nonhomogeneous Differential Equations

    Homework Statement y''+7y'=392sin(7t)+686cos(7t) with y(0)=4 and y'(0)=9 Homework Equations No real relevant equations The Attempt at a Solution I assumed since the g(t) has function of both sine and cosine the solution would be both the real and non real parts of the solution to...
  10. M

    Resistance in Series/Parallel.

    Homework Statement In the circuit below find the current I3 (in A) when R1 = 12 Ω, R2 = 78 Ω, R3 = 30 Ω, R4= 69 Ω, R5 = 72 Ω, and V = 66 V. https://s4.lite.msu.edu/res/msu/mmp/kap20/picts/hkirch2.gif Homework Equations V=iR 1/Rtotal=(1/R1+1/R2...) The Attempt at a Solution I...
  11. M

    Find Potential Minimum of Two Point Charges

    Thanks a lot! It was kind of a messy derivative but I am so thankful you helped me out. :)
  12. M

    Find Potential Minimum of Two Point Charges

    And also once I messed up enough the hint was that "A necessary condition for the potential to have a minimum is that its derivative is 0." But the derivative of what? The only thing I can think of is the V(r)=kQ/r
  13. M

    Electric Potential Energy two spheres connected by a long wire

    So wouldn't the "electrostatic potential at the surface of sphere B" be the same as A? I think the online homework expects an answer in joules which I don't really understand.
  14. M

    Electric Potential Energy two spheres connected by a long wire

    I thought the potential would be the same as well, but after I calculate the potential of the surface of the larger sphere, what charge should I use for the total? The answer I got for the surface potential of sphere B should be added to the surface potential of sphere A and that should be the...
  15. M

    Electric Potential Energy two spheres connected by a long wire

    Is there no one that can someone shed some light on the subject? Just clear things up is all.
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