Ok. So I accounted for the spin of the sphere.
New equation is (1/2)(2/5)mr^2w^2 + (1/2)mv^2 = mgh
m's cancel. I plugged in .2m for r, 5 for v, and 25 for w using v=rw. After isolating h, I multiplied by 2 to find the distance on the ramp. However, I'm still not getting the right answer... Not...
Sphere rolling up a ramp.. No mass given!
Homework Statement
A solid sphere of radius 20cm, has a velocity of 5.0m/s and is moving on a surface with just enough friction to allow it to spin. It rolls up an incline of 30 degrees. Calculate the distance rolled before it comes to rest on the...