Someone just pointed out to me my rather obvious mistake...When I subtract the 65780 "all black" hands, the rest of the hands will also still include the 65780 "all red" hands, so I should subtract those as well.
Funny how these things seem obvious in hindsight.
Thank you for replying. I can see that makes sense now.
So the best approach with these types of problems is to treat each situation separately? ie. find how many ways you can have 2 girls and 1 boy, then find how many ways you can have 3 girls and 0 boys, then add the 2 figures?
Mick
Hi all. I'm doing a counting/probability problem here.
I can see how the correct answer for part b is arrived at by counting the number of combinations for "2 girls" then counting the number of combinations for "3 girls" , and adding these results.
But I've attached my first way of approaching...