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• Yesterday, 23:26
Here is this week's POTW: Let $ABCD$ be a convex quadrilateral with $\overline{AB}=\overline{AD}$. Let $T$ be a point on the diagonal...
0 replies | 26 view(s)
• Yesterday, 23:21
No one answered this weeks POTW...my solution follows: (a) Apply conservation of angular momentum (subscripts of $R$ pertain to the rod, while...
2 replies | 144 view(s)
• Yesterday, 22:03
Comparison is fine, but it must be a VALID comparison. The idea would be capsulized as "closer to zero". Bad Example: It is also true that for x...
3 replies | 67 view(s)
• Yesterday, 13:34
$$\int_1^{\infty}\frac1x \, dx$$ does not converge. If you were to try to get an antiderivative, the only candidate is $\ln|x|$, so formally, you'd...
3 replies | 67 view(s)
• Yesterday, 00:31
\frac{5}{4}\cdot\frac{4}{3}=\frac{5}{3} :)
14 replies | 221 view(s)
• February 20th, 2018, 23:10
MarkFL posted a visitor message on Peter's profile
Sometimes editing a thread title is an issue, but the issue is with vBulletin. If you ever want to change a thread title, and can't, just let me know...
• February 20th, 2018, 17:09
I'm going to walk through this problem, using your substitution...let's begin with: I=\int_{0}^{\Large\frac{3\pi}{4}}\int_{0}^{\pi}\int_{0}^{1}...
14 replies | 221 view(s)
• February 20th, 2018, 16:49
$2^{2n+1} - 2^{2n}$ $2^{2n} \cdot 2^1 - 2^{2n}$ the two terms above have the common factor $2^{2n}$ ... $\color{red}{2^{2n}}$ $\cdot 2 -$...
5 replies | 96 view(s)
• February 20th, 2018, 16:30
Where did the $\cos(\theta)$ come from?
14 replies | 221 view(s)
• February 20th, 2018, 16:28
I was simply taught that a linear function has no concavity...just recalling from memory. :)
20 replies | 256 view(s)
• February 20th, 2018, 16:24
Let's look at an example that more clearly demonstrates the statement regarding concavity isn't always true. Consider: H(x)=\ln(x+1) And so: ...
20 replies | 256 view(s)
• February 20th, 2018, 15:58
Perhaps there are differences in terminology...I was taught that a function is concave up on an interval when its second derivative is positive, and...
20 replies | 256 view(s)
• February 20th, 2018, 15:47
Indeed, and is why I resorted to looking for a function satisfying the given criteria, that is not concave up on the given interval. :)
20 replies | 256 view(s)
• February 20th, 2018, 15:41
You want to reverse the limits of integration, because of the negative sign in the differential resulting from your $u$-substitution (I don't know...
14 replies | 221 view(s)
• February 20th, 2018, 14:55
What is the definitive test for "Concave Up"? Can you apply this test to your function?
20 replies | 256 view(s)
• February 20th, 2018, 14:54
tkhunny replied to a thread Factory Salary in Pre-Calculus
Setting up the "right equation" is the important part of the problem. You need to do it. What does "1:4" mean? What does a "ratio" look like? ...
4 replies | 72 view(s)
• February 20th, 2018, 14:47
$2^3 - 2^4$ $2^3 - 2^4$ $2^{2n+1} - 2^{2n}$ $2^{2n}(2 - 1) = 2^{2n}$ recommend you review properties of exponents
5 replies | 96 view(s)
• February 20th, 2018, 14:37
Suppose $h(t)=c$, where $0<c$...what is $H(x)$?
20 replies | 256 view(s)
• February 20th, 2018, 13:05
(c) note that $2^a(2^b) = 2^{a+b}$ ... $2^3(2^{n-1}) - 2^4(2^{n-2})$ $2^{n+2} - 2^{n+2} = 0$ use the same property of exponents for (d)
5 replies | 96 view(s)
• February 20th, 2018, 11:36
I think you did not understand my question. Not my question: Why did you tackle this problem using spherical coordinates? It was the book's...
14 replies | 221 view(s)
• February 20th, 2018, 09:13
skeeter replied to a thread Arithmetic Series in Pre-Calculus
the nth term of an arithmetic series is $a_n = a_1+(n-1) \cdot d$, where $a_1$ is the 1st term and $d$ is the common difference between each...
4 replies | 89 view(s)
• February 19th, 2018, 22:10
MarkFL replied to a thread 8.7 Two ice skaters in Physics
There were a bunch of COLOR and FONT tags all over the place that I got rid of. :)
6 replies | 88 view(s)
• February 19th, 2018, 22:04
MarkFL replied to a thread 8.7 Two ice skaters in Physics
This is what I see: My bigger concern though is all the extraneous formatting codes, some of which were embedding inside your $\LaTeX$. I do...
6 replies | 88 view(s)
• February 19th, 2018, 20:34
If: u=\cos(\phi) then: du=-\sin(\phi)\,d\phi which would result in reversing the limits of integration. :)
14 replies | 221 view(s)
• February 19th, 2018, 20:20
You should either write $$\int_{1}^{-1}(1-u^2) \, du \quad \text{or} \quad \int_{u(0)}^{u(\pi)}(1-u^2) \, du.$$ That way, you're less likely to...
14 replies | 221 view(s)
• February 19th, 2018, 20:14
MarkFL replied to a thread 8.7 Two ice skaters in Physics
As you can see, I've edited your post to remove a whole slew of extraneous formatting BBCodes...if you're going to paste your text from some other...
6 replies | 88 view(s)
• February 19th, 2018, 20:08
skeeter replied to a thread 8.7 Two ice skaters in Physics
assuming a perfectly inelastic collision (they stay together after the collision) ... initial momentum of the system = final momentum of the...
6 replies | 88 view(s)
• February 19th, 2018, 19:54
No the link was meant to be HTTPS. I was thinking that you might have the HTTP site bookmarked and could be posting through that somehow but honestly...
8 replies | 150 view(s)
• February 19th, 2018, 18:24
This is a very strange command. Why is it important that the integral came from a 'spherical coordinate' exercise? It's just an integral. Just...
14 replies | 221 view(s)
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