Recent content by Lasha

  1. L

    How do I apply Maxwell's equations?

    I don't get it how do I solve it with Gauss or Laplace when ∇×E≠0. I don't have a charge or even a region where electric field is made by a charge.I simply have sum of many circular vectors of E at any point on this surface.
  2. L

    How do I apply Maxwell's equations?

    Or does E always equal k/s cause ∇⋅E=0 where there's no charge?
  3. L

    How do I apply Maxwell's equations?

    For example, if I have a magnetic field perpendicular to some surface and I change this magnetic field with constant speed, how do I calculate the Electric field at any point on this surface, since ∫E⋅ds=k, where k is some constant, could be done with many different vector fields.
  4. L

    Learn How to Calculate g(x) with an Op-Amp Circuit | Helpful Tips and Tricks

    I've solved this.It turns out that g(x) ''breaks'' that way because of the fact that output voltage on the op-amp can't exceed supply voltage so the whole function changes.We need two op-amps in parallel so when whenever one of the output voltages reach their limits whole function doesn't become...
  5. L

    Learn How to Calculate g(x) with an Op-Amp Circuit | Helpful Tips and Tricks

    I'm trying to put this circuit in parallel with two capacitors and the inductor so it should work like a negative resistance but with function like that
  6. L

    Learn How to Calculate g(x) with an Op-Amp Circuit | Helpful Tips and Tricks

    Yes.Input voltage is that sign.X is resistance.Oh and I forgot to mention R1=R2 and R4=R5
  7. L

    Learn How to Calculate g(x) with an Op-Amp Circuit | Helpful Tips and Tricks

    So this is the circuit(with equations which were written by me, so I don’t know if they’re correct) and this is the graph I should get, but I don’t know how.( g(x) is the current vs resistance) I assume that those two equations collide somehow and I get that g(x), but I’m not sure. So my...
  8. L

    Troubleshooting a Chaotic Circuit for Lab Testing

    Thanks for the advice, I'll post an update on how it worked out.The reason I chose the breadboard over a PCB, was that I'm planning on experimenting(different combinations and values of resistance and capacity) As for the oscillator,I'm planning on buying the Sinometer ST16B 10MHz...
  9. L

    Troubleshooting a Chaotic Circuit for Lab Testing

    This is the schematic: . This is the function of a chua's diode, g(x)is resistance vs current: This is the double scroll : Yes, but shouldn't it oscillate?I highly doubt its a connection problem.
  10. L

    Troubleshooting a Chaotic Circuit for Lab Testing

    windows screen capture So I built this circuit(Chua's chaotic circuit) and I have to take it to the lab for plugging it to oscilloscope.I need to make sure it works, cause I won't have any time there to fix it or rebuild it.So when I i tested it with the multimeter,there was no voltage on the...
  11. L

    Are There Alternatives to Expensive Oscilloscopes for Signal Measurement?

    I want to measure the Chua's circuit to detect a double scroll attractor.
  12. L

    Are There Alternatives to Expensive Oscilloscopes for Signal Measurement?

    So oscilloscopes are pretty expensive and I'm a high schools student,I don't think I'll get my hands on one of those.Are there any other ways to measure the signals(an graph it of course)?
  13. L

    Why does d/dt transform to a partial derivative in the integral?

    In a normalization chapter there's an equation(1.21) which says: d/dt ∫|ψ(x,t)|^{2}dx=∫∂/∂t |ψ(x,t)|^{2}dx there was a description:(Note that integral is a function only of t,so I use a total derivative (d/dt) in the first expression,but the integrand is a function of x as well as t , so it's a...
  14. L

    Infinite Energy: Is Constant Exchange of Photons Possible?

    I am really sorry for that, it was a long ago.I assume that it was about the electrical field and I somehow understood it that way Wait so what does "losing energy to gravitational waves" mean? By Newtonian mechanics it would have been easily explained, in ideal circumstances it would move...
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