Recent content by lamefeed

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    Complex numbers: adding two fractions and solving for z

    Consider it solved! $$ \frac{z+(-z)+2}{2z-z^2}=1 \Rightarrow \frac{2}{2z-z^2} \Rightarrow 2=2z-z^2 \Rightarrow z^2-2z+2=0 \Rightarrow \frac{2\pm\sqrt{2^2-4*1*2}}{2} \Rightarrow \frac{2\pm\sqrt{-4}}{2} \Rightarrow \frac{2\pm2i}{2} \Rightarrow \\ 1 \pm i $$ I got such a good feeling when I...
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    Complex numbers: adding two fractions and solving for z

    Oh, my. I feel so embarrassed.. I'll get right to it. And when it comes to the root of ##-12## I forgot to do ## \sqrt{-12} \Rightarrow i\sqrt{4}\sqrt{3} = 2i\sqrt{3}##
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    Complex numbers: adding two fractions and solving for z

    Homework Statement $$\frac{1}{z}+\frac{1}{2-z}=1$$ Homework Equations Quadratic-formula and algebra The Attempt at a Solution Been struggling with this one.. I keep getting the wrong answer, but that isn't the worst part, I can live with a wrong answer as long as the math behind it is...
  4. L

    Understanding Complex Numbers in Equations

    Thanks for all the good suggestions :)! Starting to like doing math with complex numbers :)
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    Understanding Complex Numbers in Equations

    I've solved it, I'll take a look at the article fresh_42. The steps I took where the following: $$z=\frac{(3i+7)(1+i)}{(1-i)(1+i)} \Rightarrow \frac{3i+3i^2+7+7i}{1+i-i-i^2} \Rightarrow \frac{4+10i}{2} \Rightarrow 2+5i$$ Been struggling with that one for some time... Not sure why don't feel...
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    Understanding Complex Numbers in Equations

    Homework Statement So the problem I have is this silly little equation.. $$\frac {z - 7}{z + 3} = i $$Homework Equations This is the thing, I don't think you need anything more advanced than basic algebra to solve this problem. The Attempt at a Solution And I've tried solving it doing the...
  7. L

    Mechanical energy in situation 1 of the cart

    that might have been a mistake on my end. forgot to multiply by 2 in every part when I "made" up the formula. Pardon my English as it's not my first language.
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    Mechanical energy in situation 1 of the cart

    I tried to do so but I ended up with ~19 m/s when the speed should have been 24 m/s. It was done without knowing that the mass should have been 0.1kg
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    Mechanical energy in situation 1 of the cart

    Hehe, I get your point it's impossible to predict the mass with the velocity and height (: This was the first task based on roller coasters, the next question was asking about the speed of the cart in situation 2.. This is a badly designed problem i guess..
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    Mechanical energy in situation 1 of the cart

    The mass is unknown. Can I by any stretch of the imagination get the mass? when I only know the velocity and the height?
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    Mechanical energy in situation 1 of the cart

    Hi, I've been trying to figure out how to solve this problem for a few hours, but whatever I do it seems to give me the wrong answer. Problem statement: Fetch data from the roller coaster model. Ignore friction. What is the mechanical energy in cart in situation 1? ## E = E_k + E_p ## Which...
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    Calculating the energy in a part of a rollercoaster

    Hi(This thread might have been posted in the wrong section of the forum although this isn't a homework problem, just something I do because I like physics!), I've been trying to figure out how to solve this problem for a few hours, but whatever I do it seems to give me the wrong answer. h(1)=...
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    Calculate speed and acceleration

    Total distance is 100 m, she ran 100 m in 11.8 s, she had constant acceleration during the first 3 s after that(the remaining 8.8 s) she had constant v. s = vt s = \frac{1}{2}at^2 A combination of the two is what I suspect to be the correct formula something along the lines of this: s =...
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    Calculate speed and acceleration

    A person runs 100 m in 11.8 s. She had constant acceleration the first 3.0 s and after that she had constant speed(velocity if you will) s=vt v = v0 + at s= v0t + 1/2at^2 2as = v^2 – Vo^2 I have tried a bunch of times but I seem to get it wrong every single time. This has given me a small...
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