Kairos's latest activity

And did so wrongly if you didn't mean what I said in my previous post. Expansion and acceleration are not the same thing. No, dark...

yes, that's why I spoke of expansion in this post, and not acceleration. dark energy favors expansion contrary to gravity

Thank you. I understand that the densities decrease and lambda is left alone at the end. What I don't understand is why rho and lambda...

In a spatially flat universe the Hubble parameter is given by $$H^2=\frac{8\pi G(\rho_m+\rho_r)}{3}+\frac{\Lambda c^2}{3}$$ ##\rho_m##...

... If ##dH/dt = 0## then clearly ##\ddot a = aH^2 = \dot a^2/a## and therefore the universe is accelerating. This is also clear from...

If H will approaches a constant value given by the cosmological constant, there will still be a continuous acceleration ?(exponential).

You are completely missing the point. While k could technically be a constant in time - Hubble's original law says nothing about this...

More precisely, if k is not constant in time. Which it isn't in our universe, as you were already told in posts #3, #5, #6, #9, #13...

Orodruin, Reading other threads on the same topic, I read in one of your posts, "In fact, in a dark energy dominated universe, H is...

If k is not constant, this changes everything (but can we still talk about proportionality?). So how does the Hubble constant evolve...

OK, if k is a constant of proportionality, then the expansion is exponential and therefore accelerated.

Hubble's law certainly describes well de Sitter's universe, but beyond the details, I'm just saying that this law describes an...

This is certainly very important, but I pointed out that even if k had been constant, the expansion would still have accelerated.

of course, but that's not relevant to my question.

Velocity dx(t)/dt is proportional to distance x(t), so dx(t)/dt=k*x(t), so x(t)=exp(k*t), which accelerates with time? without the need...