Can anyone explain to me, using Dalton's Law, why a fresh cup of tead made with boiling water is not as hot at higher altitudes as it is at sea level?
I know the law is:
the law that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of the gases...
Btw, my book doe snot use 4 pie.
So I solve for E by : E = h/900 s = =1.06 x 10^-34 J/900 s? = 1.2 x 10^-37 J
Then I use E = mc^2
1.2 x 10^-37 J = m(3.0 x 10^8)^2
m = 1.54 x 10^-54 m
Is that correct! =)
I think I know how to do this problem, but need to make sure... so...
1) In an Earth reference frame, a star is 82 light years away. How fast would you have to travel so that to you the distance would only be 35 light years?
First I have two simple questions:
1. Light years is in a unit...
Yes, that would be:
(delta p)(delta x) > h or (energy)(time) > h...
So how does that help?
All I know is a time = 900 s.
So am I solving for energy? e =(1.06 x 10^-34 J)/(900 s) = 1.2 x 10^-37 J
? ? ?
This is a really simple problem, but I cannot seem to find the equation. Any help? Thank you.
1) A free neutron has a mean life of 900 s. What is the uncertainty in its mass?
Now I see. You actually manipulated the equation wrong. The Area of T is equal to AcPt/Pc. That gives the correct answer. Thanks for a good try though.
Does number two look okay?
That does stil not work. Area of copper will be 4.91 mm^2. If you then use.
A_T = \frac {\rho_C } { \rho_T A_C }
You get Area of T = .0611
and then if we use the equation of a circle for this area we get d = .27 mm.
I did all the word but my answers are not matching my books?
1) Can a 2.5 mm-diameter copper wire have the same resistence as a tungsten wire of the same length? Give numerical detials. Answer, yes, 4.6 mm
Here is what I did:
( p = resistivity )
R = p(L/A) so I set R(Cu) = R(tug) and...
Can anyone answer me a curious question. Why are electric field lines perpendicular to equipotential lines?
Is it because force and charge are inversly proportional or is there a more simple reason?
Thanks.