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Forums
johnsobertstamos
Recent content by johnsobertstamos
J
Finding the Solution: Solving for x in a Polarization of Light Equation
Yep 36, thank you everybody for your help. Much appreciated!
johnsobertstamos
Post #18
Dec 7, 2019
Forum:
Introductory Physics Homework Help
J
Finding the Solution: Solving for x in a Polarization of Light Equation
Ah so maybe it's 36 then
johnsobertstamos
Post #16
Dec 7, 2019
Forum:
Introductory Physics Homework Help
J
Finding the Solution: Solving for x in a Polarization of Light Equation
I'm inputting x = log(2/9) / log((cos 12)^2) x = 34.037
johnsobertstamos
Post #13
Dec 7, 2019
Forum:
Introductory Physics Homework Help
J
Finding the Solution: Solving for x in a Polarization of Light Equation
It gets me the same answer of 34.037 Any differences in the equations we have set up?
johnsobertstamos
Post #12
Dec 7, 2019
Forum:
Introductory Physics Homework Help
J
Finding the Solution: Solving for x in a Polarization of Light Equation
Still at a complete loss for what I'm doing wrong here. My math checks out every time.
johnsobertstamos
Post #10
Dec 7, 2019
Forum:
Introductory Physics Homework Help
J
Finding the Solution: Solving for x in a Polarization of Light Equation
1) .5((cos 12)^2)^x = 1/9 2) ((cos 12)^2)^x = 2/9 3) x ln((cos 12)^2) = ln (2/9) 4) x = (ln (2/9)) / ln((cos 12)^2) 5) x = 34.037
johnsobertstamos
Post #9
Dec 6, 2019
Forum:
Introductory Physics Homework Help
J
Finding the Solution: Solving for x in a Polarization of Light Equation
That's the phrasing given in the problem. I also forgot to mention it asks for the answer in the form of an integer.
johnsobertstamos
Post #8
Dec 6, 2019
Forum:
Introductory Physics Homework Help
J
Finding the Solution: Solving for x in a Polarization of Light Equation
The bottom one applies to just the first, reducing the intensity by half. The top one applies to the rest of the polarization stages.
johnsobertstamos
Post #4
Dec 6, 2019
Forum:
Introductory Physics Homework Help
J
Finding the Solution: Solving for x in a Polarization of Light Equation
Sorry, should be 1/9
johnsobertstamos
Post #3
Dec 6, 2019
Forum:
Introductory Physics Homework Help
J
Finding the Solution: Solving for x in a Polarization of Light Equation
I set up the equation .5((cos 12)^2)^x = 1/9 Solving for x gets me 34.037 34 + 1 = 35 I've entered answers of both 34 and 35 and both have been marked as wrong. Does anybody know what I'm doing wrong here?
johnsobertstamos
Thread
Dec 6, 2019
Tags
Light
Polarization
Replies: 17
Forum:
Introductory Physics Homework Help
Forums
johnsobertstamos
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