Recent content by johnsobertstamos

  1. J

    Finding the Solution: Solving for x in a Polarization of Light Equation

    Yep 36, thank you everybody for your help. Much appreciated!
  2. J

    Finding the Solution: Solving for x in a Polarization of Light Equation

    I'm inputting x = log(2/9) / log((cos 12)^2) x = 34.037
  3. J

    Finding the Solution: Solving for x in a Polarization of Light Equation

    It gets me the same answer of 34.037 Any differences in the equations we have set up?
  4. J

    Finding the Solution: Solving for x in a Polarization of Light Equation

    Still at a complete loss for what I'm doing wrong here. My math checks out every time.
  5. J

    Finding the Solution: Solving for x in a Polarization of Light Equation

    1) .5((cos 12)^2)^x = 1/9 2) ((cos 12)^2)^x = 2/9 3) x ln((cos 12)^2) = ln (2/9) 4) x = (ln (2/9)) / ln((cos 12)^2) 5) x = 34.037
  6. J

    Finding the Solution: Solving for x in a Polarization of Light Equation

    That's the phrasing given in the problem. I also forgot to mention it asks for the answer in the form of an integer.
  7. J

    Finding the Solution: Solving for x in a Polarization of Light Equation

    The bottom one applies to just the first, reducing the intensity by half. The top one applies to the rest of the polarization stages.
  8. J

    Finding the Solution: Solving for x in a Polarization of Light Equation

    I set up the equation .5((cos 12)^2)^x = 1/9 Solving for x gets me 34.037 34 + 1 = 35 I've entered answers of both 34 and 35 and both have been marked as wrong. Does anybody know what I'm doing wrong here?
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