Recent content by jmorgan

  1. J

    MHB Maximizing Likelihood Estimator of β

    Assuming α is known, find the maximum likelihood estimator of β f(x;α,β) = , 1 ,,,,,,, .(xα.e-x/β) ,,,,,, ,,,,,,α!βα+1 I know that firstly you must take the likelihood of L(β). But unsure if I have done it correctly. I came out with the answer below...
  2. J

    MHB Showing Superposition: u(x, t) Equation

    Hi, I can't quite understand how to do this question please could someone help :) Show, by the principle of superposition, that u(x, t) = ∞ ∑ An sin(npix)e2n2pi2t n=1 where A1, A2,..., are arbitrary constants. Thanks
  3. J

    MHB How Does Separation of Variables Solve the Heat Equation in a Metal Rod?

    Re: Seperation of Variables/ODE Ignore my previous reply, I now have: XT' = kX''T divide both by kXT to get: T'/kT = X''/X so T'/kT = µ and X''/x = µ (this is where G'(t)=k µG and F''(x)= µF is required) now I am stuck on how to solve these.
  4. J

    MHB How Does Separation of Variables Solve the Heat Equation in a Metal Rod?

    Re: Seperation of Variables/ODE I have began by : XT' = kX''T rearrange: T'/T=kX''/X=\alpha trying to solve: T'/T=\alpha and kX''/X=\alpha and that is the furthest I can go
  5. J

    MHB How Does Separation of Variables Solve the Heat Equation in a Metal Rod?

    The temperature distribution u(x, t), at time t > 0, along a homogeneous metal rod can be obtained by solving the 1d heat equation; ut = kuxx (1) where k = 2 is a constant. The length of the rod is 1m and the temperature at either end of the rod is zero for all time, so that the boundary...
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