Recent content by jeff einstein

?

This makes the most sense to me. The way i perceive this root (-x)^2 is the same as (-1*x)^2 and so when squaring the negative 1 it becomes positive and that just makes the equation root x^2 and so the root of a (-x) squared number is always. Is this right?

Just to clear up (i think this is where my confusion arises from), the square root of a number (negative or positive) is always the absolute value of the number?

Sir please give respect to my teacher and plus i don't really understand your argument here please explain this with math

so both sides become absolute values of X?

I have a very basic confusion that supports some basic elements of algebra. Being a high school student my teacher couldn't answer this, hope someone could help here. We know this equation is true: (-x)^2=x^2 but once we square root both sides it becomes this: -x=x we can see this equation was...

i like this explanation, this is what I am saying, here @jack action has put an approximate sign of 0 and not completely equal. All I am saying is even though the mass of the smaller object may have a very very very small effect on the earth it still is present. I think I am done with this...

two factors affect the fall of the object the distance between the centers and the mass of both objects involved. we can agree that increasing the distance away from the center must influence the rate of "fall" and so likewise increasing or decreasing mass should also affect the rate of fall.

don't overcomplicate everything all I want to know is if this is true. because I have now concluded that however small the mass maybe it still has its own gravity and so must influence its fall toward the earth.

Very much thank you for this i sure couldn't read that

i agree what i am trying to say is that even if invert the machine the wrench will still move but in the opposite. this is because the reaction force and the force applied is the same but one force is farther way from the pivot compared to the other. that is my theory

i know the diagram is inaccurate i only want to know if any "machine" like such would work.

i want to know if the machine will cause the wrench to turn clockwise not to remain stationary

but the moment of the forces are different

ok, i have got it now this simple answer is way easier to understand compared to the others on the older thread. so the effect I am talking about is actually present but too small to realize