Recent content by JamesB93

I was thinking that, wasn't sure if it was acceptable to do so. My lecturers haven't been too clear through this year. It gives the same result so I'm guessing that's what I'm supposed to do. Thanks :)

EDIT: I had an idea I could just assume the exit velocity roughly to see how much difference it made. As the general guidance from the question is to give answers in kJ/kg and rounded to 2dp, a velocity of less than 3m/s makes absolutely no difference to the outcome. With the emphasis on "very...

Homework Statement This is a question from an exam that my university determined to be so harsh that they allowed resits with uncapped grades. I'm going to be taking such a resit thus I'm trying to figure out the paper: Air at 10oC and 80 kPa enters the diffuser of a jet engine steadily with...

Okay if I account for the pressure drop and use it to alter the mass of the air as it enters the engine, then follow on with those numbers I get 71.98 horsepower. Checking online I can see that the maximum output of one the 1.4 litre Vauxhall Corsa 5 speed manuals are in the range 85-100. I'll...

Those are my (very) rough notes on the engine power output so far. Apologies for the handwriting, combination of dyslexia and recovering collarbone. As I said previously, the calorific value of the fuel is in kJ/kg.K and I haven't accounted for the K on the end of that and I haven't accounted...

I seem to have had a clarifying moment, I was taking the air:fuel ratio for volume, not mass. I did ((pi*bore2)/4)*stroke to get the swept volume of each cylinder. I then multiplied that by 4 to get the total swept volume of the engine and divided it by 2 because the pistons only intake air on...

I'm currently studying Mechanical Engineering at Level 3 in the UK and I'm beginning my integrated masters in September. I've missed a large chunk of my studies this year due to a broken collarbone I sustained earlier in the year. Instead of getting any special dispensation I'm trying to work my...