Sorry, the v1' at the end was a typo.
So then with
v1 + v1' = v2' and
m1(v1 - v1') =m2v2' which becomes (m1(v1 - v1')) / m2 = v2'
I would do v2' = v2' to get
v1 + v1' = (m1(v1 - v1')) / m2
v1' = ((m1(v1 - v1')) / m2 ) - v1
Is this correct? And from here, how do I go on to the wanted...
After simplifying the equations, I got:
m1(v1-v1') = m2v2' (momentum) and
m1(v1-v1')(v1+v1') = m2v2'^2 (kinetic energy)
From there, I'm not sure what to do. I referred to a textbook and it said to divide the energy equation by the momentum equation (the simplified versions) and then do a...