29 m/s is the horizontal velocity before it goes up the hill that is 22m high. I just figured it out though. Did an energy balance between the bottom and top of the hill instead of after it falls and the top of the hill. Because of that I was getting the wrong velocity value.
A solid, uniform ball rolls without slipping up a hill. At the top of the hill it is moving horizontally; then it goes over the vertical cliff. V= 29 m/s and H= 22.0m
A) How far from the foot of the cliff does the ball land?
B) How fast is it moving just before it lands?
Been stuck on this...
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